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AfilCa [17]
4 years ago
10

Which of these is a simplified form of the equation 7x + 4 = 5 + 3x + 1x?

Mathematics
2 answers:
Katarina [22]4 years ago
4 0
7x+4=5+3x+1x
7x+4=5+3x+x
7x+4=5+4x
7x-4x=5-4
3x=1
x= 1/3

svetoff [14.1K]4 years ago
3 0
Your answer is going to be <span>3x=1.</span>
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0=(x+2) squared minus 25
hichkok12 [17]

Answer:

x=3

Step-by-step explanation:

0=(x+2)^2-25

+25 +25

25=(x+2)^2

Square root both sides to get:

5=x+2

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3=x

8 0
2 years ago
Read 2 more answers
Find the value of x.
dmitriy555 [2]

Answer:

x = 57°

Step-by-step explanation:

The angle not 76° or x° is 180-133 which is 47°. A triangles angles always sum up to 180° so:

76°+47°+x°=180°

123°+x°=180°

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6 0
3 years ago
A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0
3 years ago
There are 12 donuts in a box 1/3 of them are chocolate, 1/4 of them are sprinkles, and the rest are glazed. How many donuts are
zmey [24]

Answer:

3 donuts are sprinkles

Step-by-step explanation:

1/3 of 12 is 4

1/4 of 12 is 3

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5 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs, not all tiles will be used.
Ann [662]

Answer:

I can't answer your question because I can't see what boxes your talking about

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