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3 years ago

14

PLZ!!! HELP. Blake has traveled 65% of the distance to his grandpearents house. he traveled 26 miles. how many total miles will

he travle?

2 answers:

8090 [49]3 years ago

4 0

Answer:

40

Step-by-step explanation:

mafiozo [28]3 years ago

3 0

Answer:

40 I think so if not I hate u

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Prove that every integer greater than 7 can be written by using 3's and 5's only. that is, for every n > 7 there exist non-ne

Taya2010 [7]

An integer may be a multiple of 3.
An integer may be 1 greater than a multiple of 3.
An integer may be 2 greater than a multiple of 3.

It is redundant to say an integer is 3 greater than a multiple of 3 (that's just a multiple of 3, we've got it covered). Same for 4, 5, 6, 7...

Let's consider a number which is a multiple of 3. Clearly, we can write 3+3+3+3+... until we reach the number. It can be written as only 3's.

Let's consider a number which is 2 greater than a multiple of 3. If we subtract 5 from that number, it'll be a multiple of 3. That means we can write the number as 5+3+3+3+3+... Of course, the number must be at least 8.

Let's consider a number which is 1 greater than a multiple of 3. If we subtract 5 from that number, it'll be 2 greater than a multiple of 3. If we subtract another 5, it'll be a multiple of 3. That means we can write the number as 5+5+3+3+3+3+... Of course, the number must be at least 13.

That's it. We considered all the numbers. We forgot 9, 10, 11, and 12, but these are easy peasy.

Beautiful question.

4 0

3 years ago

Consider the example of finding the probability of selecting a black card or a 6 from a deck of 52 cards.

Marina86 [1]

Answer:

The probability of selecting a black card or a 6 = 7/13

Step-by-step explanation:

In this question we have given two events. When two events can not occur at the same time,it is known as mutually exclusive event.

According to the question we need to find out the probability of black card or 6. So we can write it as:

P(black card or 6):

The probability of selecting a black card = 26/52

The probability of selecting a 6 = 4/52

And the probability of selecting both = 2/52.

So we will apply the formula of compound probability:

P(black card or 6)=P(black card)+P(6)-P(black card and 6)

Now substitute the values:

P(black card or 6)= 26/52+4/52-2/52

P(black card or 6)=26+4-2/52

P(black card or 6)=30-2/52

P(black card or 6)=28/52

P(black card or 6)=7/13.

Hence the probability of selecting a black card or a 6 = 7/13 ....

7 0

4 years ago

Pls answer this with a picture showing the correct box plot

faust18 [17]

Answer/Step-by-step explanation:

To find out the mistake of the student, let's find the min, max, median, Q1 and Q3, which make up the 5 important values that are represented in a box plot.

Given, {2, 3, 5, 6, 10, 14, 15},

Minimum value = 2

Median = middle data point = 6

Q1 = 3 (the middle value of the lower part of the data set before the median)

Q3 = 14 (middle value of the upper part of the data set after the median)

Maximum value = 15

If we examine the diagram the student created, you will observe that he plotted the median wrongly. The median, which is represented by the vertical line that divides the box, ought to be at 6 NOT 10.

See the attachment below for the correct box plot.

3 0

3 years ago

The data below are the monthly average high temperatures for New York City. What is the five-number summary? 40, 40, 48, 61, 72,

yawa3891 [41]

Answer:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

Step-by-step explanation:

The first step is to write the temperatures in crescent order:

40, 40, 42, 48, 54, 61, 65, 72, 76, 78, 84, 84,

The sample minimum is the lowest value = 40

The sample maximum is the highest value = 84.

Since there are 12 numbers, the sample median is the average between the 6th and 7th terms:

$M = \frac{61+65}{2}\\ M=63$

The first quartile is the average between the 3rd and 4th terms:

$Q_1 = \frac{42+48}{2}\\ Q_1=45$

The third quartile is the average between the 9th and 10th terms:

$Q_3 = \frac{76+78}{2}\\ Q_3=77$

Therefore, the answer is:

B) Sample minimum: 40, Sample maximum: 84

Q1: 45, Median: 63, Q3: 77

8 0

3 years ago

Jeremy ate 5 pieces of shrimp, Julie ate 7 pieces. What fraction of the total did Jeremy eat?

matrenka [14]

Answer:

$\frac{5}{12}$

Step-by-step explanation:

The total amount of shrimp that was eaten was 12 pieces of shrimp.

To make the fraction you will simply put the amount of shrimp Jeremy ate over the total number of shrimp eaten by the pair.

Therefore, the fraction would look like this:

$\frac{5}{12}$

The decimal form of this would be 0.4167. Which also means that Jeremy ate 41.67% of the total amount of shrimp eaten.

Hope this helps!!

4 0

2 years ago