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zhenek [66]
3 years ago
9

104. Find the inverse g for each function f. a. f(x) = 1/2x-3

Mathematics
1 answer:
ch4aika [34]3 years ago
6 0
Change f(x) y to make it easier.
y = 1/2x-3
switch y and the x.
x = 1/2y-3
Add 3 to both sides
x+3 = 1/2y
Multiply both sides by 2.
2x+6 = y
Therefore, f^-1(x) = 2x+6
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Answer:

12 pigs and 20 chickens

Step-by-step explanation:

Chicken = 2 legs

Pig = 4 legs

(15 * 4) + (17 * 2) = 88                          NO

(12 * 4) + (20 * 2) = 88                         Yes, and 12 + 20 = 32

7 0
2 years ago
What is the perimeter of a rectangle that has a length of 40 Ft and a width of 17 ft?
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Step-by-step explanation:

5 0
1 year ago
Read 2 more answers
Please help I will mark brainlist if correct
djyliett [7]
Solving for L:

P = 2L + 2W
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8 0
3 years ago
In a survey of 300 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want
bixtya [17]

Answer:

<h2>0.05543</h2>

Step-by-step explanation:

The formula for calculating the margin of error is expressed as;

M.E = z * \sqrt{\frac{p*(1-p)}{n} } where;

z is the z-score at 95% confidence = 1.96 (This is gotten from z-table)

p is the percentage probability of those that watched network news

p = 40% = 0.4

n is the sample size = 300

Substituting this values into the formula will give;

M.E = 1.96*\sqrt{\frac{0.4(1-0.4)}{300} }\\ \\M.E = 1.96*\sqrt{\frac{0.4(0.6)}{300} }\\\\\\M.E = 1.96*\sqrt{\frac{0.24}{300} }\\\\\\M.E = 1.96*\sqrt{0.0008}\\\\\\M.E = 1.96*0.02828\\\\M.E \approx 0.05543

Hence, the margin of error for this survey if we want 95% confidence in our estimate of the percent of T.V. viewers who watch network news programs is approximately 0.05543

5 0
3 years ago
In a carnival​ game, a person wagers​ $2 on the roll of two dice. if the total of the two dice is​ 2, 3,​ 4, 5, or 6 then the pe
Olin [163]

Answer: a loss of 4 cents

<u>Step-by-step explanation:</u>

The probability of rolling a sum of 2, 3, 4, 5, or 6 is \dfrac{15}{36} which earns $2.00

The probability of rolling a sum of 28, 9, 10, 11, or 12 is \dfrac{15}{36} which loses $2.00

The probability of rolling a sum of 7 is \dfrac{6}{36} which loses $0.25

\bigg(\dfrac{15}{36}\times \$2.00\bigg)+\bigg(\dfrac{15}{36}\times -\$2.00\bigg)+\bigg(\dfrac{6}{36}\times -\$0.25\bigg)=\boxed{-\$0.04}

6 0
3 years ago
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