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lora16 [44]
3 years ago
10

Help please! I will mark brainliest

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0

Answer:

I hope this will be good for u :)

lbvjy [14]3 years ago
5 0

Answer:

Step-by-step explanation:

∠L = 52

∠N  = 26

8) ∠M + ∠N = 180          {in trapezoid, LM // PN, co interior angles}

    ∠M +  26 = 180

              ∠M = 180 - 26

              ∠M = 154

11) ∠LPN + ∠L = 180        {in trapezoid, LM // PN, co interior angles}

     ∠LPN + 52 = 180

                ∠LPN = 180 - 52

∠LPN = 128

9)In ΔPAN,

∠PAN + ∠N + ∠NPA = 180 {Angle sum property}

90 + 26 + ∠NPA = 180

         116 + ∠NPA = 180

                  ∠NPA = 180 - 116

                   ∠NPA = 64

∠LPA + ∠NPA = ∠LPN

∠LPA +  64  = 128

            ∠LPA = 128 - 64

           ∠LPA = 64

10) ∠MAP = 90                    {PA ⊥ MN}

               

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What is the solution set of y=2x^2+8x and x-2.23y+10.34=0
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First, let's put the second equation, <span>x-2.23y+10.34=0, in terms of y:
x - 2.23y +10.34 = 0   
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Now we can substitute the right side of this equation for y in the first equation
</span><span>y=2x^2+8x
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Turn it into a quadratic by getting 0 on one side:
2x^2 + 8x - .45x - 4.64 = 0
2x^2 + 7.55x - 4.64 = 0 Divide both sides by 2
x^2 + 3.76x - 2.32 = 0
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Plug the x values into y = .45x + 4.64
y = .45 (.54) + 4.64
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y = .45 (-4.31) + 4.64
y = 2.70 when x= -4.31

Solution set:
{ (0.54, 4.88) , (-4.31, 2.70) }
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