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V125BC [204]
3 years ago
5

Given the equation -4x+3y=-17 find the value of y if the ordered pair (2,y) is a solution

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0

Answer:

-3

Step-by-step explanation:

First - change the equation to y=mx+b format

3y/3 = 4x/3 - 17/3

y = 4/3x - 17/3

Second - then (2,y) plug x = 2

Third - solve

y = 4/3(2) - 17/3

y = 8/3 - 17/3 = -9/3 = -3

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tamaranim1 [39]
<span>173/<span>25 is the answer to that.</span></span>
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3 years ago
If x-12y=-210and x-6y=90 then x =
Whitepunk [10]

Answer:

90

Step-by-step explanation:

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6 0
2 years ago
How to <br> Write <br> 3/9<br> in simplest form.
White raven [17]
To write it in simplest form, you must find a common factor.

In \frac{3}{9}, 3 is a factor of both 3 and 9

3÷3=1 and 9÷3=3

So \frac{3}{9} =  \frac{1}{3}

\frac{1}{3} is your answer in simplest form.
3 0
3 years ago
For what value of c is the function defined below continuous on (-\infty,\infty)?
kozerog [31]
f(x)= \left \{ {{x^2-c^2,x \ \textless \  4} \atop {cx+20},x \geq 4} \right&#10;

It's clear that for x not equal to 4 this function is continuous. So the only question is what happens at 4.
<span>A function, f, is continuous at x = 4 if 
</span><span>\lim_{x \rightarrow 4} \  f(x) = f(4)

</span><span>In notation we write respectively
</span>\lim_{x \rightarrow 4-} f(x) \ \ \ \text{ and } \ \ \ \lim_{x \rightarrow 4+} f(x)

Now the second of these is easy, because for x > 4, f(x) = cx + 20. Hence limit as x --> 4+ (i.e., from above, from the right) of f(x) is just <span>4c + 20.
</span>
On the other hand, for x < 4, f(x) = x^2 - c^2. Hence 
\lim_{x \rightarrow 4-} f(x) = \lim_{x \rightarrow 4-} (x^2 - c^2) = 16 - c^2

Thus these two limits, the one from above and below are equal if and only if
 4c + 20 = 16 - c²<span> 
 Or in other words, the limit as x --> 4 of f(x) exists if and only if
 4c + 20 = 16 - c</span>²

c^2+4c+4=0&#10;\\(c+2)^2=0&#10;\\c=-2

That is to say, if c = -2, f(x) is continuous at x = 4. 

Because f is continuous for all over values of x, it now follows that f is continuous for all real nubmers (-\infty, +\infty)

4 0
3 years ago
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rusak2 [61]

Answer:

G

Step-by-step explanation:

3 0
2 years ago
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