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3 years ago

A 15 foot tall tree casts a shadow that is 8 feet long. What is the distance from the top of

Mathematics

1 answer:

Aloiza [94]3 years ago

7 0

Answer:

17 feet

Step-by-step explanation:

15^2 + 8^2 = 17^2

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Find the total area for the regular pyramid.<br><br><br><br> T. A. =

Allisa [31]

The total area is:
A = Ab + Al
Where,
Ab: base area
Al: lateral area
We have then:
For the base area:
Ab = (2) * (2)
Ab = 4 units ^ 2
For the lateral area:
Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
Al = (4) * (root (1 + 9))
Al = 4raiz (10) units ^ 2
Total area:
A = 4 + 4raiz (10)
Answer:
A = 4 + 4raiz (10)

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3 years ago

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A woman is 59 and one twelfth inches tall and her son is 57 and five ninths inches tall. How much taller is the woman?

mihalych1998 [28]

Answer:

1 and 19/36 inches

Step-by-step explanation:

All you have to do is subtract the woman's height by her son's height.

59 and 1/12 - 57 and 5/9 is 1 19/36

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2 years ago

I need help now I don't get this

Darina [25.2K]

The answer is $1.80. You would take 25% of 3, which is 75, and subtract it from 3. That leaves you with $2.25, which you take 20% off, which is 0.45, and subtract that from 2.25. That leaves you with a grand total of $1.80. Hope that this helped!

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3 years ago

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Plz help long division those 4

expeople1 [14]

I would tell you how to do it but its a very hard thing to explain

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2 years ago

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How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0

ziro4ka [17]

Answer:

$\displaystyle x = \frac{\pi}{3} +k\, \pi$ or $\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ , where $k$ is an integer.

There are three such angles between $0$ and $2\pi$ : $\displaystyle \frac{\pi}{3}$ , $\displaystyle \frac{2\, \pi}{3}$ , and $\displaystyle \frac{4\,\pi}{3}$ .

Step-by-step explanation:

By the double angle identity of sines:

$\sin(2\, x) = 2\, \sin x \cdot \cos x$ .

Rewrite the original equation with this identity:

$2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0$ .

Note, that $2\, (2\, \sin x \cdot \cos x)$ and $(-2\, \sin x)$ share the common factor $(2\, \sin x)$ . On the other hand, $2\sqrt{3}\, \cos x$ and $(-\sqrt{3})$ share the common factor $\sqrt[3}$ . Combine these terms pairwise using the two common factors:

$(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0$ .

Note the new common factor $(2\, \cos x - 1)$ . Therefore:

$\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0$ .

This equation holds as long as either $\left(2\, \sin x + \sqrt{3}\right)$ or $(2\, \cos x - 1)$ is zero. Let $k$ be an integer. Accordingly:

$\displaystyle \sin x = -\frac{\sqrt{3}}{2}$ , which corresponds to $\displaystyle x = -\frac{\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = -\frac{2\, \pi}{3} + 2\, k\, \pi$ .
$\displaystyle \cos x = \frac{1}{2}$ , which corresponds to $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ and $\displaystyle x = -\frac{\pi}{3} + 2\, k \, \pi$ .

Any $x$ that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

$\displaystyle x = \frac{\pi}{3} + k \, \pi$ (from $\displaystyle x = -\frac{2\,\pi}{3} + 2\, k\, \pi$ and $\displaystyle x = \frac{\pi}{3} + 2\, k \, \pi$ , combined,) as well as
$\displaystyle x =- \frac{\pi}{3} +2\,k\, \pi$ .

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3 years ago