Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
Hello <span>Pouerietzach
</span><span>
Question: Which of the following is the term for the topmost folder in a directory?
Answer: Root Folder (A)
Hope That Helps!
-Chris</span>
Answer: Image preloading
Explanation:
The Image Preloading process can be describes as follows:
1. Using the new keyword an instance of the image object is created.
2. The src property and the flename of the image is set be equal.
3. Then image is downloaded into the cache with displaying it.
4. The src property is set equal to the prefetched image when it is required to display the image.
I can’t find how to do this
