Answer:
See explaination
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
this means that size of nut is smaller than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
this means that size of bolt is smaller than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
Answer:
1.word = "George slew the dragon"
startIndex = word.find('dr')
endIndex = startIndex + 4
drWord = word[startIndex:endIndex]
2. sentence = "Broccoli is delicious."
sentence_list = sentence.split(" ")
firstWord = sentence_list[0]
Explanation:
The above snippet is written in Python 3.
1. word is initialized to a sentence.
Then we find the the occurence of 'dr' in the sentence which is assign to startIndex
We then add 4 to the startIndex and assign it to endIndex. 4 is added because we need a length of 4
We then use string slicing method to create a substring from the startIndex to endIndex which is assigned to drWord.
2. A string is assigned to sentence. Then we split the sentence using sentence.split(" "). We split based on the spacing. The inbuilt function of split returns a list. The first element in the list is assigned to firstWord. List uses zero based index counting. So. firstWord = sentence_list[0] is use to get first element.
Answer:
See explaination
Explanation:
#include <iomanip>
#include <string>
#include <fstream>
using namespace std;
void getName(string);
void getPin(int,int);
void displayMenu(int);
string name;
int pin1, pin2, ch ;
int main()
{
cout << fixed << showpoint << setprecision(2);
getName(name);
getPin(pin1,pin2);
displayMenu(ch );
system("pause");
}
void getName(string name)
{
cout << "Enter your name: ";
cin >> name;
if (name = "AXBY") || (name != "ABGSHY"))
{
getName(name);
}
}
void getPin(int pin1, int pin2)
{
string name;
if (name == "AXBY")
{
cout << "Please Enter Pin: ";
cin >> pin1;
if (pin1 != 4433)
{
cout << "Pin incorrect please try again!";
cin >> pin1;
}
}
if (name == "ABGSHY")
{
cout << "Please Enter Pin: ";
cin >> pin2;
if (pin2 != 2849)
{
cout << "Pin incorrect please try again!";
cin >> pin2;
}
}
}
void displayMenu(int ch )
{
cout << "[1] Check your account Balance\n"
"[2] Withdraw funds\n"
"[3] Deposit funds\n"
"Please Enter Choice: ";
cin >> ch ;
if (ch != 1 || ch != 2 || ch != 3)
{
cout << "Choice is incorrect, enter choice now: ";
cin >> ch ;
}
}
False, the storage is being accessed from the cloud which can only be accessed through an internet connection.
I've had that problem before. The cause of my problem was 2 things and that was the age of the cable, and build up of dust on each of the cable.
