Answer:
Number of strings = (10, 2)×(8,3) = 2520
Explanation:
The number of possible combinations for taking two 0's is C(10, 2)
It remains 8 Positions
The number of possible combinations for taking three 1's is C(8,3)
So there remains 5 spots
Answer: The answer is anonymity
Explanation: i had the same question on my test.
Click Tools and select Windows Firewall with Advanced Security.
Review the current configuration settings by selecting Windows Firewall Properties from the MMC landing page. You can access and modify the settings for each of the three firewall profiles, Domain, Private, and Public, as well as IPSec settings.
Answer:
10
Explanation:
An enqueue operation is a function that adds an element(value) to a queue array. A dequeue operations removes an element from a queue array. Queue arrays follow a first-in-first-out approach, so elements that are first stored in the queue are removed/accessed first(enqueue operations add elements at the rear of the queue array).
The following operations leave 10 elements in the queue of array size 12 after its done:
10 enqueue operations= adds 10 elements
5 dequeue operations= removes 5 elements( 5 elements left in queue)
6 enqueue operations= adds 6 elements(11 elements in queue)
10 dequeue operations= removes 10 elements(1 element left in queue)
8 enqueue operations= adds 8 elements(9 elements in queue)
2 dequeue operations= removes 2 elements(7 elements left in queue)
3 enqueue operations= adds 3 elements(10 elements in queue)
Therefore there are 10 elements in the queue after enqueue and dequeue operations.
