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horrorfan [7]
3 years ago
10

Luciana is adding water to a pool at a constant rate. Before she added any water, the pool had $12,000$ gallons of water. Lucian

a is adding $9$ gallons of water each minute.
Which equation represents the total number of gallons of water in the pool, $w$ , after Luciana adds water for $m$ number of minutes?
Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

T(m) = 12,000 gallons + (9 gallons/ minute)m

Step-by-step explanation:

This is a linear function with beginning value 12,000 gallons and unit rate of increase 9 gallons/minute:

T(m) = 12,000 gallons + (9 gallons/ minute)m

PS:  Please don't use " $ " to set off numbers.  Not needed!

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2 years ago
For a certain bathtub, it takes the hot water faucet
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\bf \begin{array}{cccccclllllll}
\cfrac{1}{c}&+&\left( \cfrac{1}{3}\cdot \cfrac{1}{c} \right)&=&\cfrac{1}{6}\\\\
\cfrac{1}{c}&+&\cfrac{1}{3c}&=&\cfrac{1}{6}\\\\
\uparrow &&\uparrow &&\uparrow \\
\textit{cold water rate}&&\textit{hot water rate}&&\textit{total done by both}
\end{array}\\\\
-----------------------------\\\\

\bf \cfrac{3+1}{3c}=\cfrac{1}{6}\implies 24=3c\implies \cfrac{24}{3}=c\implies \boxed{8=c}
\\\\\\
\textit{now, if the cold water faucet can do it in 8 minutes by itself}\\\\
\textit{then the hot water faucet can do it in 3 times as long}
\\\\\\
3\cdot 8\implies \boxed{24}
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