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V125BC [204]
3 years ago
12

Consider the expansion of (x + 2y)^10. Determine the coefficients for the terms with the powers of x and y shown.

Mathematics
2 answers:
julsineya [31]3 years ago
7 0

Answer with Step-by-step explanation:

We are given that  an expression

(x+2y)^{10}

Binomial expansion o f (x+y)^n is given by

=nC_0 x^n+nC_1x^{n-1}y^1+nC_2x^{n-2}y^2+nC_3x^{n-3}y^3+... nC_n y^n

a. We have to find the coefficient of x^2y^8

(x+2y)^{10}=10C_0x^{10}+10C_1x^9(2y)+10C_2x^8(2y)^2+10C_3x^7(2y)^3+...+10C_{10}(2y)^{10}

Term is 10C_8x^(2y)^8

Coefficient =10C_8\cdot 2^8

b.Term in which x^4y^6  is 10C_6x^4(2y)^6

Coefficient =10C_4\cdot 2^6

c.We have to find the coefficient of x^5y^5

Term  is 10C_5x^5(2y)^5

Coefficient =10C_5\cdot 2^5

kifflom [539]3 years ago
3 0

Answer:

Step-by-step explanation:

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