( this is sum by gcf ) 15+81= (+__)? what is the gcf of 15 and 81

2 answers:

8 0

$15+81=3(5+27) \to 3*32 =\boxed{96} \\\\ 15|3 \\ 5 \ |5 \\ 1 \\\\15=3*5 \\\\\\ 81|3 \\ 27|3 \\ 9 \ |3 \\ 3 \ |3 \\ 1 \\\\ 81=3^4 \\\\ G.C.F(15;81)=3$

mixer [17]3 years ago

4 0

$15+81=3\cdot5+3\cdot27=3(5+27)$

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4 0

3 years ago

David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o

BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :( $b^4,b^2,b^4$ )

$b^4$ = b × b × b × b

$b^2$ = b × b

$b^4$ =b × b × b × b

GCF of variables :( $b^4,b^2,b^4$ ) is $b^2$

3) GCF of $c^3$ and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.