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Alina [70]
3 years ago
12

A 20 year par value bond with semi-annual coupons at a nominal annual rate of 8% convertible semi-annually is purchased at a pri

ce of 1783.27. The bond can be called at par value X on any coupon date starting at the end of year 12 after the coupon is paid. The price guarantees a nominal annual rate of interest convertible semi-annually of at least 6%. Calculate X.
Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

3.216%

Step-by-step explanation:

This bond sells at a higher price or value, which means that its coupon is bogus of market interest rate. Therefore, the minimum yield rate that accounts for the possibility of the bond being called is calculated at the earliest possible call date. Let say exactly 15 years from the date of purchase, because that would be the most disadvantageous date for the bondholder for the call to occur.

The minimum semiannual yield:

j= i²/2

i² = 2j

which therefore satisfies the expression below for the worst possible case scenario yield:

1722.25 = 0.04*1100*a]_30+\frac{1100}{(1+j)^30}

Also, with the use of a financial calculator (making sure that the calculator is not in BGN mode)

1722.25 PV, -44 PMT, -1100 FV, 30 N, CPT 1/Y.

j can be found to be 1.608245%. The corresponding nominal annual rate compounded semiannually is (X) = i² = 2j =3.216%

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Winston deposited $3,294 in a bank account with an annual interest rate of 2.6%. How much interest was earned in 5
ale4655 [162]

Answer:

FV= $3,725.07

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $3,294

Number of periods (n)= 5 years

Interest rate (i)= 2.6% = 0.026

<u>To calculate the future value (FV), we need to use the following formula:</u>

FV= PV*(1+i)^n

FV= 3,294*(1.026^5)

FV= $3,725.07

3 0
3 years ago
What is the equation, in standard form, of a parabola that contains the following points?
svp [43]

Answer:

D

Step-by-step explanation:

the the 5 minus the 12 and the 0 minus the negative one all finds it way. back to the equation d

5 0
3 years ago
Part a at what speed v should an archerfish spit the water to shoot down an insect floating on the water surface located at a di
loris [4]
3.01 m/s  
This is a simple projectile calculation. What we want is a vertical velocity such that the time the droplet spends going up and going back down to the surface exactly matches the time the droplet takes to travel horizontally 0.800 meters. The time the droplet spends in the air will is:
 V*sqrt(3)/2 ; Vertical velocity.
 (V*sqrt(3)/2)/9.8 ; Time until droplet reaches maximum height
 (V*sqrt(3))/9.8 ; Double that time for droplet to fall back to the surface.
 
 The droplet's horizontal velocity will be:
 V/2.
 
 So the total distance the droplet travels will be:
 d = (V*sqrt(3))/9.8 * V/2
 d = V^2*sqrt(3)/19.6
 
 Let's substitute the desired distance and solve for V
 d = V^2*sqrt(3)/19.6
 0.8 = V^2*sqrt(3)/19.6
 15.68 = V^2*sqrt(3)
 15.68/sqrt(3) = V^2
 15.68/1.732050808 = V^2
 3.008795809 = V 
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 Let's verify that answer.
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8 0
3 years ago
A rectangle has a height to width ratio of 3:4.5. Give two examples of dimensions for rectangles that could be scaled versions o
OlgaM077 [116]

We have been given that a rectangle has a height to width ratio of 3:4.5.

Let h be height and w be width of rectangle.

We can set our given information in an equation as:

\frac{h}{w} =\frac{3}{4.5}

h=\frac{3}{4.5} *w

Now we will substitute h=1 in this equation.

1=\frac{3}{4.5} *w

3w=4.5

w=\frac{4.5}{3} =1.5

We can see that width of rectangle is 1.5 times height of rectangle.

Our one set of dimensions of rectangle will be: height=1 and width=1.5.

We can get many set of dimensions for our rectangle by multiplying both height and width of rectangle by same number.

Multiplying by 5 we will get our dimensions as: height 5 and width 7.5.  

Therefore, (1 and 1.5) and (5 and 7.5) dimensions for rectangle will be scaled version of our rectangle.

6 0
3 years ago
Can someone please solve this, tell me which one goes where in order.​
sasho [114]

Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

Solution:

Cost for single ticket = t dollars

Discount percent per ticket = 5%

Number of tickets bought = 10

Total discount for 10 group tickets = Number of tickets × Discount amount

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Total discount for 10 group tickets = 10 · 0.05t

Amount of discount per ticket = 5%t

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                                                  = 0.05t

Amount of discount per ticket = 0.05t

Number of tickets = 10

Cost of buying 10 single tickets = 10t

4 0
4 years ago
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