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2 years ago

HELP PLEASE 50 POINTS Write your personal reaction to this event. An embarrassing moment

Mathematics

2 answers:

mixas84 [53]2 years ago

6 0

Answer:

what i did or tried to do after an embarrssing moment

Step-by-step explanation:

Ignore it. There are times when you're lucky enough to sidestep an embarrassing moment just before it's about to happen or it happens but nobody's paying attention.

Zigmanuir [339]2 years ago

4 0

Answer:

is it an essay writing????

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Show step by stephow to solve this problem 2001 - 1682

expeople1 [14]

So first you subtract 2001-1682=319.
There is just 1 step, and it is hard to show work here.
Hope this helped! :)

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3 years ago

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What is the median of these numbers: 1, 2, 3, 3, 4, 6, 8, 9, 10?

monitta

Answer: 4

Step-by-step explanation: The answer is 4 because, to find the median you must put the numbers in order and find the one in the middle . Which makes the answer 4 :)

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2 years ago

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It would be so greatly appreciated if you could help me with my geometry work!!!!

Zolol [24]

Answer:

m<BCA+m<BCD=180

Step-by-step explanation:

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3 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

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3 years ago

You earn $20.00 per hour at your job. If you get a 10% raise at the end of each year, what will your hourly rate, h, be after 8

love history [14]

R is the rate (10%)
C=20, begiing rate
T=time=8

so

h=20(1+0.10)^8
h=20(1.1)^8
h=42.8718
ronnd

$42.87

D is answer

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3 years ago