Answer:
<h3><em><u>hey</u></em><em><u> </u></em><em><u>mate</u></em><em><u> </u></em><em><u>here</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>ur</u></em><em><u> </u></em><em><u>answer</u></em><em><u>:</u></em><em><u>---------------------------------------------------</u></em></h3>
<h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0</u></em></h3><h3 /><h3><em><u>1) f (x) = x 3 + 2x 2 - 8x first factor of x ------> x( x^2 +2x -8) = 0 -------> x = 0 and x^2 +2x -8 = 0 Now, you find b^2 -4ac that in this case will be = 2^2 -4*1*(-8) = 4 + 32 = 36 it means this equation has 2 different real roots and will be (-b ±√b^2 - 4ac) / 2a ------> x = 2 , -4 as result #1 has 3 real roots such as 0,2,-4</u></em></h3>
<h3><em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em></h3><h3><em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>✌</u></em></h3>
Answer:
(2x-3) (2x+3)
zeros, x intercepts: -3/2, 3/2
Step-by-step explanation:
4x^2 -9
We know the difference of squares is a^2 -b^2
This factors into (a-b) (a+b)
Let 4x^2 =a^2
Taking the square root
2x =a
Let b^2 =9
Taking the square root
b= 3
(4x^2-9 ) = (2x-3) (2x+3)
To find the zeros, we set the equation equal to zero
(4x^2-9 ) = (2x-3) (2x+3) =0
Using the zero product property
2x-3 =0 and 2x+3 =0
2x-3+3 = 0+3 2x+3-3 = 0-3
2x=3 2x=-3
Divide by 2
2x/2 = 3/2 2x/2 = -3/2
x = 3/2 x = -3/2
These are the zeros of the equation (which are also the x intercepts)
You dived 14.28/4.2 by taking the decimal out and when you get the answer put it back
