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Hunter-Best [27]
3 years ago
14

Kara knitted 1/5 of the cap in the morning. Bu evening, she had knitted 7/10 of the cap. How much of the cap she knitted during

the afternoon?
Mathematics
1 answer:
nadya68 [22]3 years ago
6 0
Convert 1/5 to 2/10 and then 7/10 minus 2/10 is 5/10 which is equivalent to 1/2. Ask anytime;)
You might be interested in
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista
poizon [28]
The rate of Car A is x
The rate of Car B is x - 5

They travel the same distance. So we can make an equation:

4(x) = 4.5(x-5)

Solve for x.

4(x) = 4.5(x-5)
4x = 4.5x - 22.5

Subtract 4.5x on both sides

-0.5x = -22.5

Divide by -0.5 on both sides
x = 45

But we want the speed of Car B which is x - 5

So Car B's speed is 45 - 5 = 40

Your answer is 40
8 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
un rectangulo tiene 28 cm de perimetro y unos de sus lados mide 4 cm ¿cuantos cuadrados de 2 cm por lado se mecesitan para armar
seraphim [82]

Answer:

10 cuadrados

Step-by-step explanation:

Si uno de los lados de rectangulo es de 4cm entonces el lado parallelo tambien es de 4cm. Eso nos da 8cm del perimetro y nos quedan los otros dos lados que tienen la misma medida. Entonces dividimos el resto del perimetro por 2.

28 - 8 = 20cm

20cm / 2cm = 10cm

Ahora que tenemos todas las medidas podemos multiplicar el largo por el ancho para calcular el area del rectangulo

10cm * 4cm = 40cm^{2}

el cuadrado de 2cm tendra un area de

2cm * 2cm = 4cm^{2}

Ahora simplemente dividimos el area del rectangulo por el area del cuadrado para saber cuantos cuadrados necesitamos para armar ese rectangulo

40cm^{2} / 4cm^{2} = 10 cuadrados

3 0
2 years ago
(8 times 10 to the fourth power)+(4 times 10 to the fourth power)
Aliun [14]

Answer:

120,000

Step-by-step explanation:

8 times 10 to the 4th power is 80,000 and 4 times 10 to the 4th power is 40,000 and 80,000 plus 40,000 is 120,000

8 0
3 years ago
Jorge gives an equal number of marbles to 6 friends. Which could be the total number of marbles he gave to his friends?
Allushta [10]

Answer:

D. 60

Step-by-step explanation:

To find an equal number of numbers the sum has to be equal to 6*x.

6 0
3 years ago
Read 2 more answers
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