<h3><u>25</u> ( <u>13</u><u> </u> - <u>3</u><u>)</u></h3><h3> 6 ( 3 2)</h3>
<u>25</u><u> </u><u> </u>( <u>39 -9)</u>
6 (6)
<u>2</u><u>5</u><u> </u> × <u>30</u>
6 6
<u>125</u>
6
20 <u> 5</u><u> </u><u> </u> [ans]
6
You can try finding the roots of the given quadratic equation to get to the solution of the equation.
There are two solutions to the given quadratic equation
<h3>How to find the roots of a quadratic equation?</h3>
Suppose that the given quadratic equation is 
Then its roots are given as:
<h3>How to find the solution to the given equation?</h3>
First we will convert it in the aforesaid standard form.
Thus, we have
a = 1. b = -114, c = 23
Using the formula for getting the roots of a quadratic equation,
Thus, there are two solutions to the given quadratic equation
Learn more here about quadratic equations here:
brainly.com/question/3358603
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Ivan can make 11 toy cabins and has 12 sticks left over.
The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
