Answer:
(y+2)=2(x−3)
Or
(y−4)=2(x-6)
Or
y=2x−8
Step-by-step explanation:
Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)




Substituting the first three equations into the fourth allows us to solve for

:

For each possible value of

, we get two corresponding critical points at

.
At these points, respectively, we get a maximum value of

and a minimum value of

.
Answer:
1/4
Step-by-step explanation:
12/4= 3
Each paid $3 but as a fraction 3/12=1/4
Answer:
<h2>
y = x² - 1</h2>
Step-by-step explanation:
y = -1 for x = 0 {point(0, -1)} means -1 at the end of formula
If we add 1 to y-coordinate of every given point we get the squares of x-coordinate:
(1, 0): 1² - 1 = 0
(2, 3): 2² - 1 = 4 - 1 = 3
(3, 8): 3² - 1 = 9 - 1 = 8
(4, 15): 4² - 1 = 16 - 1 = 15
So for any x:
(x, y) y = x² - 1
The correct answer for the exercise shown above is:
zero (0)
The explanation is shown below:
1. You have the following expression given in the problem above:
7/6a
2. By definition, <span>the nonpermissible replacement for a is the value that make the denominator equal to zero.
3. Keeping this on mind, you have:
7/6a=7/6(0)=7/0
Therefore, as you can see, the answer is: zero (a=0).
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