It’s unsolvable with out more context. What’s the rest of the problem.

r - radius, h - height
The diameter is twice the radius.

The answer is c. 791.3 m³.
(20 + 22 + 17) - 7 - 12 - (9 - x) = 37;
59 - 19 - 9 + x = 37;
31 + x = 37;
x = C) 6
Set equations for both containers:
Condition one: $y=2x$
Condition two: $(y-3)=4.5(x-2)$
plug in $y$ from condition one into the second equation:
$2x-3=4.5x-9$
simplify gives: $2.5x=6$
$\boxed{x=2.4}$
$\boxed{y=4.8}$