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vfiekz [6]
3 years ago
8

53kg, 42kg, 41kg, 60kg, 44kg, 49kg. Calculate the mean weight giving your answer correct to two decimal places

Mathematics
1 answer:
mylen [45]3 years ago
3 0
Mean is simply the average of all numbers and to find it you add up all the numbers and divide for how many numbers there are (in this case we 6 numbers, 6 masses).

So, 53+42+41+60+44+49 = 289 kg

Mean = 289/6 = 48,1666666....

So 48,17 is your answer
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4 years ago
The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
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Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
4 years ago
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