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storchak [24]
3 years ago
10

Yuk noticed that out of 24 students entering the building at Willowville Elementary School this morning, 8 of them were carrying

a lunch box. If these students are representative of the entire school, how many of the Willowville's 84 students would you expect to have brought a lunch box?
Mathematics
1 answer:
nordsb [41]3 years ago
3 0

Answer:

the students that brought a lunch box is 28

Step-by-step explanation:

The computation of the students that brought a lunch box is shown below:

= Entire school students × students that carry a lunch box ÷ entering students

= 84 students × 8 ÷ 24 students

= 28 students

Hence, the students that brought a lunch box is 28

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soldi70 [24.7K]

Answer:

c. 69

b. 7

Step-by-step explanation:

4 0
2 years ago
Which set of points includes all of the solutions for y = negative three halves times x plus two? line going through 0 comma 2 a
worty [1.4K]

Answer:

(x,-\frac{3}{2} x+2)

Step-by-step explanation:

For y= \frac{-3}{2} x+2  the set of points that include all solutions are (x,y) such that   y= \frac{-3}{2} x+2; then we have (x,y)=(x,\frac{-3}{2} x+2).

What is important to stress here is that (x,-\frac{3}{2} x+2) represents all of the solutions, while other points that we are given represent one solution  (for example, point (2,-1) is just one solution)

5 0
3 years ago
Given sin A = 12/13 and that angle A is in Quadrant 1,
UkoKoshka [18]

We have been given that \text{sin}(A)=\frac{12}{13} and angle A is in quadrant 1. We are asked to find the exact value of \text{cot}(A) in simplest radical form.

We know that sine relates opposite side of right triangle with hypotenuse.

\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}

This means that opposite side is 12 units and hypotenuse is 13 units.

We know that cotangent relates adjacent side of right triangle with adjacent side.

\text{cot}=\frac{\text{Adjacent}}{\text{Opposite}}

Now we will find adjacent side using Pythagoras theorem as:

\text{Adjacent}^2=\text{Hypotenuse}^2-\text{Oppoiste}^2

\text{Adjacent}^2=13^2-12^2

\text{Adjacent}^2=169-144

\text{Adjacent}^2=25

Let us take positive square root on both sides:

\sqrt{\text{Adjacent}^2}=\sqrt{25}  

\text{Adjacent}=5

Therefore, adjacent side of angle A is 5 units.

\text{cot}(A)=\frac{5}{12}

Therefore, the exact value of cot A is \frac{5}{12}.

5 0
3 years ago
Sue drank 2/5 of her water bottle and sally drank 4/10 of her water bottle how much water did both girls drank?
stealth61 [152]

well, clearly the LCD from the denominators of 5 and 10 is just 10, thus

\bf \stackrel{\textit{Sue}}{\cfrac{2}{5}}+\stackrel{\textit{Sally}}{\cfrac{4}{10}}\implies \stackrel{\textit{LCD of 10}}{\cfrac{(2)2~~+~~(1)4}{10}}\implies \cfrac{2+4}{10}\implies \cfrac{6}{10}\implies \stackrel{\textit{simplified}}{\cfrac{3}{5}}

3 0
3 years ago
Which of the following are true statements about angle parking. Angle parking spots have a larger blind spaces than perpendicula
S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

Angle parking spots have half the blind spot as compared to perpendicular parking spaces

Step-by-step explanation:

Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.

Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."

Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."

5 0
3 years ago
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