Improper fraction 8517/1000 and as the mixed number 8 and 517/1000
Answer:
its either 3 or 4
Step-by-step explanation:
Answer: The average daily inventory is 200 cases.
Step-by-step explanation:
Since we have given that
N(t)=600-20√30t
We need to find the average daily inventory.
![\dfrac{1}{b-a}\int\limits^a_b {600-20\sqrt{30t}} \, dt\\\\=\dfrac{1}{30}\int\limits^{30}_0 {600-20\sqrt{30t}} \, dt \\\\=\dfrac{1}{30}[600t-\dfrac{20(30t)^\frac{3}{2}}{45}|_0^{30}\\\\=\dfrac{1}{30}[18000-\dfrac{20\times 30^3}{45}]\\\\=\dfrac{1}{30}[18000-12000]\\\\=200](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bb-a%7D%5Cint%5Climits%5Ea_b%20%7B600-20%5Csqrt%7B30t%7D%7D%20%5C%2C%20dt%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B30%7D%5Cint%5Climits%5E%7B30%7D_0%20%7B600-20%5Csqrt%7B30t%7D%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B30%7D%5B600t-%5Cdfrac%7B20%2830t%29%5E%5Cfrac%7B3%7D%7B2%7D%7D%7B45%7D%7C_0%5E%7B30%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B30%7D%5B18000-%5Cdfrac%7B20%5Ctimes%2030%5E3%7D%7B45%7D%5D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B30%7D%5B18000-12000%5D%5C%5C%5C%5C%3D200)
Hence, the average daily inventory is 200 cases.
Answer: 1 2/3
Step-by-step explanation:
The expression to find the perimeter of a rectangle is 2(length + width)
Length = 1/3
Width = 1/2
Perimeter = 2( 1/3 + 1/2)
Lowest common factor = 6
Perimeter = 2 [ (2 + 3) / 6]
Perimeter = 2 [ 5/6]
Perimeter = 10/6
Perimeter = 1 4/6 = 1 2/3
Answer:
<em>2j+7</em>
Step-by-step explanation:
<u>Phrase Into Algebraic Expression</u>
If a problem is correctly phrased, it should be easily translated into algebraic language by following simple and concrete rules.
We have the phrase:
<em>7 more than twice Jose's height.</em>
Usually, we first deal with products and divisions before sums and subtractions because of the natural order of mathematic operations.
In the given phrase, the '7 more' part is left to the end and we start with the 'twice' part because it's a product.
Since we are using the variable j for Jose's height, then twice Jose's height is 2j.
Now we finish the expression by adding 7: 2j+7
Thus, the translation to algebraic expression is: 2j+7
