All categories

3 years ago

F(3)= 5x^2 - 4x + 9 evaluate this quadratic function

Mathematics

1 answer:

Neporo4naja [7]3 years ago

6 0

Answer:

$f(3) = 38$

Step-by-step explanation:

Given the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

Evaluating the quadratic function

$f\left(x\right)=\:5x^2\:-\:4x\:+\:9$

substitute x = 3

$f\left(3\right)=\:5\left(3\right)^2\:-\:4\left(4\right)\:+\:9$

$f(3) = 45-16+9$

$f(3) = 38$

Therefore,

$f(3) = 38$

You might be interested in

Factor the equation please help

LiRa [457]

Answer:

For A

${ \rm{6 {x}^{2}(x + 1) - 2x(x + 1) }}$

• The equation above has a common bracket "(x + 1)". So, let's first factorise out that bracket:

$\dashrightarrow \: { \rm{(x + 1) \{6 {x}^{2} - 2x \} }}$

• now in the second bracket, the common factor is x and 2.

$\dashrightarrow \: { \rm{(x + 1) \{2x(3x - 1) \}}}$

• Final answer;

${ \boxed{ \boxed{ \rm{ \dashrightarrow \: 2x(x + 1)(3x - 1) \: \: }}}}$

For B

${ \rm{3(x - 1)(x + 2) + ( {x}^{2} - x)(x + 2) }}$

• In the equation, the common bracket is (x + 2).

So let's first factorise it out:

$\dashrightarrow \: { \rm{(x + 2) \{3(x - 1) + ( {x}^{2} - x) \}}} \\ \\ { \rm{(x + 2) \{3(x - 1) + x(x - 1) \}}}$

• In the second major bracket, the common bracket is (x - 1). so factorise it out:

${ \rm{(x + 2) (x - 1) \{3 + x \}}}$

• Final answer:

${ \boxed{ \boxed{ \rm{ \dashrightarrow \: (x + 2)(x + 3)(x - 1) \: \: }}}}$

8 0

3 years ago

Multiply: (5x − 2)(4x2 − 3x − 2)?

Ronch [10]

Answer:

-140

Step-by-step explanation:

Are thoses X's multiplication

6 0

3 years ago

De un pliego rectangular de foami que mide 96 cm de largo por 72 cm de ancho,se requiere cortar cuadros de la mayor superficie p

kykrilka [37]

I do not understand ur language I speak English very well sorry I can't help you with your homework

7 0

3 years ago

What is the answer to -6-(-2)=

Irina-Kira [14]

Answer:

-4

explanation:

since there is subtraction sign in front of the negative 2 it would change into a positive 2.

-6 + 2 = -4

8 0

3 years ago

Read 2 more answers

How do you find the missing length in Pythagorean

kotegsom [21]

If this pertains to the Pythagorean theorem, then the answer that you would most likely to end up with is by utilizing the equation a² + b² = c² where a and b are the legs of the triangle and c is the hypotenuse. The hypotenuse refer to the longest side of the triangle while the other two would be the legs of the triangle.

When solving for the missing length, just substitute the values given to their respective places in the equation. If a length of a leg is missing, then substitute the other leg's value to either a or b, then substitute the length of the hypotenuse to c. Then solve. Solving for the hypotenuse's length would be a lot easier than the legs.

3 0

3 years ago