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LuckyWell [14K]
3 years ago
8

In the circle with center $O$, the measure of $\angle RIP$ is $36^\circ$ and $OR=10$ cm. Find the number of centimeters in the l

ength of arc $RP$. Express your answer in terms of $\pi$.

Mathematics
1 answer:
alina1380 [7]3 years ago
7 0

Answer:

3pi

Step-by-step explanation:

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) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.
yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the  0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= \dfrac{1}{2}

The length of bits : n = 10

Let X = Number of getting ones.

Then , X \sim Bin(n=10,\ p=\dfrac{1}{2})

Binomial distribution formula : P(X=x)=^nC_x p^x q^{n-x} , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , p=q=\dfrac{1}{2}

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}

=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}

=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})

=(\dfrac{1}{2})^{10}(210+252)

=(0.0009765625)(462)

=0.451171875\approx0.4512

Hence, the  probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0
4 years ago
what is 10 x 10 x 10 divided by 9? ik but my comments r maxed out for this one place and yall get points
topjm [15]

Answer:

10 x 10 x 10 divided by 9? =111.111111111

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22.09 is the product
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Step-by-step explanation:

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What is 8x43 in expanded form
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<span>Well, 8 * 43 = 344:

Word from- Eight * forty-three = three hundred forty-four

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</span>
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