To solve this
problem, let us analyze this step by step. The temperature for each day is as
follows:
Water temperature
on Sunday = 78 degrees F
Water temperature
on Monday = changed by -3 degrees F
Water temperature
on Tuesday = changed by 3 degrees F
We can see that
the total change of water temperature from Sunday to Tuesday is:
-3 + 3 = 0
Therefore there
is zero overall change. There the integer which represents the temperature
change is “0”.
Since the overall
change in water temperature is zero, hence the temperature on Sunday and on
Tuesday is similar.
Water temperature
on Tuesday = 78 degrees F
Hello : the system is :
<span> y= -2x+4 ...(1)
y= x² +4x+13....(2)
x²+4x+13 = -2x+4
x²+6x+9=0
(x+3)² =0
x+3=0
x= -3
subsct in (1) : y=-2(-3)+4 =10</span>
SOH CAH TOA
—>
Sin D = 13 sqrt3/26 = 0.76
Sin E = 13/26 = 0.47
Cos D = 13/26 = 0.87
Cos E = 13 sqrt3/26 = 0.64
Let x represent the shorter sides, then 2x + 1 would represent the longer sides. There are four short sides and two long sides. The perimeter is 162 cm. The equation: 4x + 2(2x + 1) = 162 4x + 8x + 2 = 162 8x + 2 = 162 Subtract 2 from both sides. 8x = 160 Divide both sides by 8. x = 20 The shorter sides are 20 cm in length. The longer sides are 2x + 1, or 41 cm in length. Check: 4 * 20 + 2 * 41 = 162 80 + 82 = 162 162 = 162, values check.
