I need help I will give brainiest

Mathematics

1 answer:

malfutka [58]3 years ago

4 0

5. (X,y)=(7,23)
One solution

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3 years ago

PLEASE HELP IF YOU CAN!

Masteriza [31]

$\bf \begin{array}{ccllll}
term&value\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
a_1&9.5\\
a_2&11.5\\
a_3&13.5\\
a_4&15.5\\
...&...
\end{array}\\\\
-----------------------------\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term}\\
d=\textit{common difference}
\end{cases}$

notice, the first term is 9.5
from there it goes to 11.5, well, how much is it being added to get 11.5?
well 9.5 + 2, is 11.5, so it was added 2 to 9.5

then it goes from 11.5 to 13.5, namely, 11.5+2 = 13.5
and then 13.5+2 = 15.5 and so on

so, the "common difference" or the common addition value, is 2
how do you find the nth term?

well $\bf a_n=9.5+(n-1)2\iff a_n=9.5+2(n-1)$