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bulgar [2K]
2 years ago
10

An aircraft flew 5 hours with the wind. The return trip took 6 hours against the wind. If the speed of the plane in still air is

260 miles per hour more than the speed of the​ wind, find the wind speed and the speed of the plane in still air.
I need this solved asap.
Mathematics
1 answer:
Yakvenalex [24]2 years ago
5 0

Answer:

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

Step-by-step explanation:

Given:

Time taken with wind = 5 hour

Time taken against wind = 6 hour

Assume;

Speed of wind = s

So,

Speed of Plane with wind = (260 + s) miles per hour

Speed of Plane against wind = (260 - s) miles per hour

Distance = speed x time

So,

(260 + s)5 = (260 - s)6

1,300 + 5s = 1,560 - 6s

11s = 260

s = 23.63 miles per hour

Speed of wind = 23.63 miles per hour

Plane speed in still air = 260 miles per hour

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Murrr4er [49]

Choice A is the answer which is the point (1,-1)

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How I got this answer:

Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.

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checking choice A

plug in (x,y) = (1,-1)

y - 2x \le -3

-1 - 2(1) \le -3

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This is true because -3 is equal to itself. So this is the answer.

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checking choice B

plug in (x,y) = (2,4)

y - 2x \le -3

4 - 2(2) \le -3

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This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.

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checking choice C

plug in (x,y) = (-2,3)

y - 2x \le -3

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This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.

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checking choice D

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3 years ago
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rosijanka [135]
<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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and the function g(x) is given by:

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        f(x)=g(x)

i.e. we have to find the value of x such that both the functions are equal i.e.

x^2-x-12=-1.8x-0.6\\\\i.e.\\\\x^2-x+1.8x-12+0.6=0\\\\i.e.\\\\x^2+0.8x-11.4=0\\\\i.e.\\\\10x^2+8x-114=0\\\\i.e.\\\\5x^2+4x-57=0

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