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umka2103 [35]
2 years ago
15

Identify the reference angle

Mathematics
1 answer:
ser-zykov [4K]2 years ago
7 0

Answer:

Below in bold.

Step-by-step explanation:

300 degrees - reference angle is |360 - 300 |= 60 degrees

225 = 225 - 180 = 45 degrees

480 = 480 - 360 = 120 so it is 180 - 120 = 60 degrees.

-210 = |-210 + 180| = 30 degrees.

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A party of 5 wants to tip 20% of their total $175 bill. If divided evenly, how much should each person tip?
Mashcka [7]
20% of $175 is $35. Divided between 5 people (35/5=7) would be 7. So each person should tip $7.
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The profits in hundreds of dollars, P(c), that a company can make from a product is modeled by a function of the price, c, they
Jobisdone [24]
The maximum profit is the y-coordinate of the vertex of the parabola represented by the equation.

P(c)=-20c^2+320c+5120 \\ \\
a=-20 \\
b=320 \\ \\
\hbox{the vertex } (h,k): \\
h=\frac{-b}{2a}=\frac{-320}{2 \times (-20)}=\frac{-320}{-40}=8 \\
k=f(h)=f(8)=-20 \times 8^2+320 \times 8+5120= \\
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The maximum profit the company can make is $640,000.
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Tpy6a [65]

I think the answer is B

6 0
2 years ago
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Help please, will give lots of points!
Troyanec [42]

Step-by-step explanation:

roots as exponents are fractions

if there is no root number next to the radical sign its assumed that its 1/2

3√2 is 2^(1/3)

√3 is 3^(1/2)

4√3 is 3^(1/4)

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8 0
2 years ago
Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

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