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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
Answer:
(- 4, - 10 )
Step-by-step explanation:
Given the 2 equations
y = x - 6 → (1)
x = - 4 → (2)
Substitute x = - 4 into (1) for corresponding value of y
y = - 4 - 6 = - 10
Solution is (- 4, - 10 )
The answer is If you would like to find the expression that is equivalent to (t*s)(x), you can calculate this using the following steps:
s(x) = x - 7
t(x) = 4x^2 - x + 3
(t*s)(x) = t(s(x)) = t(x - 7) = <span>4(x - 7)^2 - (x - 7) + 3 = 4(x - 7)^2 - x + 7 + 3
The correct result would be </span>4(x – 7)2 – (x – 7) + 3.
Answer:
x = 57°
Step-by-step explanation:
The angle not 76° or x° is 180-133 which is 47°. A triangles angles always sum up to 180° so:
76°+47°+x°=180°
123°+x°=180°
x°=57°
Answer:
D
Step-by-step explanation:
8590 x 0.03 = 257.70
._.