Two parallel lines are cut by a transversa

A worker is exposed to 98 dB for five hours and 82 dB for three hours, giving an eight-hour working day. On average, what noise

julia-pushkina [17]

Answer:

92 dB

Step-by-step explanation:

Use the mean formula, mean = sum of elements / number of elements.

Since it is a 8 hour work day, there are 8 elements.

mean = sum of elements / number of elements

mean = (98 + 98 + 98 + 98 + 98 + 82 + 82 + 82) / 8

mean = 736 / 8

mean = 92

So, the average noise level is 92 dB

6 0

2 years ago

Help me! Answer in pic not correct !

sladkih [1.3K]

Answer:

$Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)$

Step-by-step explanation:

First we have to find the coordinates of the original ordered pairs then we will do the translation.

$Q=(1,3)\\R=(3,-3)\\S=(0,-2)\\T=(-2,1)$

Now we will add 3 to every x value and add a -2 to every y value.

$Q=(1_{+3},3_{+(-2)})\\R=(3_{+3},-3_{+(-2)})\\S=(0_{+3},-2_{+(-2)})\\T=(-2_{+3},1_{+(-2)})$

When you do that you will get the new prime points.

$Q'=(4,1)\\R'=(6,-5)\\S'=(3,-4)\\T'=(1,-1)$

8 0

3 years ago

Solve the quadratic equation by factoring-

shtirl [24]

Answer:

c- (2x+3)(x+1)

Step-by-step explanation:

Let me know if you want step by step

3 0

3 years ago

ammie pays $30 for a bag that she buys at a discount of 50%. What is the price of the bag without the discount? A. $30 B. $45 C.

Liula [17]

This would be C. 60$

This is because if she got the bag for 50% off, 30 divided by 2 is 15$, 45 divided by 2 is 22.5, 60 divided by 2 is 30$ so option C. Would be your answer.

7 0

3 years ago

XYZ Corporation operates two plants, each of which has a capacity of 100 units per day. Each day, XYZ must ship their product to

Strike441 [17]

9514 1404 393

Answer:

{20, 20, 20, 40} units to {A, B, C, D}
{0, 0, 0, 100}

minimum shipping cost: 3000

Step-by-step explanation:

In general, shipping costs more from Plant 1. The excess costs to ship to customers A, B, C, D are, respectively, (24-18) = 6, (21-16) = 5, (19-19) = 0, (18-10) = 8.

The greatest excess cost is for shipping to customer D from plant 1, so we want to ship as many units as possible to customer D from plant 2.

Shipments from Plant 2 to Customers {A, B, C, D} = {0, 0, 0, 100}.

Then the remaining shipments are fulfilled from Plant 1.

Shipments from Plant 1 to Customers {A, B, C, D} = {20, 20, 20, 40}.

The amount spent on shipping each day is ...

100×10 +20×24 +20×21 +20×19 +40×18

= 20×(50 +24 +21 +19 +36) = 3000 . . . . daily shipping cost

6 0

2 years ago