$\displaystyle\\
 -3\tan^2x + 1 = 0\\\\
 -3\tan^2x = -1\\\\
\tan^2x = \frac{-1}{-3} \\\\
\tan^2x = \frac{1}{3} ~~~~~ \Big|~\sqrt{~~~} \\\\
\sqrt{\tan^2x} = \sqrt{\frac{1}{3}} \\\\
\tan x = \Big| \frac{1}{ \sqrt{3} } \Big|\\\\
\tan x = \Big| \frac{\sqrt{3}}{ 3 } \Big|\\\\
\tan x = \frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_1= \frac{\pi}{6} + k\pi,~~k \in N \\\\ 
\tan x = -\frac{\sqrt{3}}{ 3 }~~~\Longrightarrow~~x_2= \pi-\frac{\pi}{6} + k\pi = \frac{5\pi}{6} + k\pi,~~k \in N \\\\ 
$

4 0

3 years ago

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M<2 = 34. Find m<4 and explain how you know.

Basile [38]

Answer:

m<4 = 34°

Step-by-step explanation:

m<2 = 34° (given)

m<3 + m<2 = 180° (linear pair)

m<3 + 34° = 180° (substitution)

Subtract 34° from each side

m<3 = 180° - 34°

m<3 = 146°

m<4 + m<3 = 180° (linear pair)

m<4 + 146° = 180° (substitution)

Subtract 146° from each side

m<4 = 180° - 146°

m<4 = 34°

This shows that vertical angles are congruent.

m<2 and m<4 are vertical angles formed when two straight line intersects. They are both of equal measure.

3 0

3 years ago