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Anit [1.1K]
3 years ago
6

First get the gcf of 16x³ + 250 which is 2 then divide it which has the result of 8x³ + 125 then get the square root of 8x³ and

125
Mathematics
1 answer:
Lina20 [59]3 years ago
6 0
(-5/2, 0) hope this helps
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The number of girls at middle school Cyber summer camp was six more than twice the number of boys. The total of 156 middle schoo
Sloan [31]
Girls: 81
boys: 75

4x +6 = 156
4x = 150
x = 37.5
2x = 75

girls: 75 + 6
boys: x
7 0
3 years ago
Which pair of transformations moves quadrilateral 1 to quadrilateral 2?
malfutka [58]

Translate it 8units to the right then reflect it over the line y=-3

Why?

  • We can see the Quadrilateral is in Quadrant 3.
  • If we translate it by 8units right it come to Quadrant 4.
  • Now reflect it over line y=-3
  • we will get Quadrilateral 2
6 0
3 years ago
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Evaluate the series 4 – 2 + 1 – 0.5 + 0.25 to S10. Round to the nearest hundredth.
aleksklad [387]
The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by

S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}\\\\S_{10}=4\cdot \dfrac{(-\frac{1}{2})^{10}-1}{-\frac{1}{2}-1}=4\cdot \dfrac{(\frac{1}{1024}-1)}{(-\frac{3}{2})}\\\\=\dfrac{8}{3}\cdot \dfrac{1023}{1024}=\dfrac{341}{128}

The sum is approximately 2.66.
4 0
3 years ago
Which expression is equal to 5^4 x 5^8 ? <br><br> A: 5^12<br> B: 5^4<br> C: 5^2<br> D: 5^−4
galben [10]

Something to remember is how to multiply terms with same bases, but different exponents:

a^b \cdot a^c = a^{(b+c)}


Essentially, we add the exponents.


Using the information above, we can find our answer:

5^4 \cdot 5^8 = 5^{(4+8)} = \boxed{5^{12}}


Our answer is \boxed{5^{12}}, or A.

6 0
3 years ago
Read 2 more answers
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

3 0
3 years ago
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