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Genrish500 [490]
3 years ago
6

Calculate the mean,median and mode.(3 points each)

Mathematics
1 answer:
Marizza181 [45]3 years ago
5 0

Answer:

1. The first set of number is

1,2,3,4,5

Mean= 1+2+3+4+5/5

= 15/5

= 3

Median= 3

Mode= N/A

The next set of numbers is

2,3,4,5,6,6

Mean= 2+3+4+5+6+6/6

= 26/6

= 4.3

Median=4+5/2

= 9/2

= 4.5

Mode= 6

The next set of number is

6,7,5,4,5,6,2,5

Mean= 2+4+5+5+5+6+6+7/8

= 40/8

= 5

Median= 5+5/2

= 10/2

= 5

Mode= 5

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Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

or

b > 3\frac{2}{15}\\\\

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

2 & 3/5 = (2*5 + 3)/5

2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality 2 \frac{3}{5} < b - \frac{8}{15}\\\\ is the same as \frac{13}{5} < b - \frac{8}{15}\\\\

---------------------

Let's multiply both sides by 15 to clear out the fractions

\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\

---------------------

Now isolate the variable b

39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

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3 years ago
Which property of real numbers is shown below? -6(4x + 5) = -24x - 30 associative property of addition commutative property of m
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This is an example of The Distributive Property.

We can tell this because the number on the outside of the parenthesis on the left side has been distributed to each number inside on the right. You do this by multiplying each number by the number on the outside.

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What is the value of x and the length of segment DE?
aniked [119]

Answer:

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Step-by-step explanation:

Assume the diagram is like the figure below.

1. Calculate the value of x

In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the triangle into two similar triangles.

Thus, ∆CDF ~ ∆FDE, and

\begin{array}{rcl}\dfrac{CD}{DF} &=& \dfrac{FD}{DE}\\\\\dfrac{5}{9} &=& \dfrac{9}{2x + 3}\\\\5(2x + 3) & = &81\\10x + 15 & = & 81\\10x & = & 66\\x & = & \mathbf{6.6}\\\end{array}

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Answer: infinitely many solutions.

Step-by-step explanation:

Ok, our equation is:

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now, simplifyng the right side, we have:

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-2.1*b + 5.3 = -2.1*b + 5.3

So in both sides of the equality we have the exact same thing, so this is a trivial equality.

This means that the equality will remain true for any value of b, which means that we have infinitely many solutions.

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