Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
<span>
.
</span>
Answer:
2
Step-by-step explanation:
Rise is 10 run is 5 Rate of Change is rise over run.
Answer:
A
Step-by-step explanation:
Perpendicular lines have a relationship between their slopes. Their slope are negative inverses of each other. This means is one is 3 then the negative reciprocal is the other or -1/3. The slope here is 1/9 so the perpendicular slope is -9. Slope is always attached to the x term so A is the solution.
4 * 2 = 8
8 + 5 = 13
B, is the correct answer
Answer:
-4
Step-by-step explanation:
f(-1) = 2(-1) - 2 = -4
