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marissa [1.9K]
2 years ago
10

Find the perimeter of the following figure. ​

Mathematics
2 answers:
avanturin [10]2 years ago
7 0

Answer:

10 meters

Step-by-step explanation:

Perimeter= 3+3+2+2

=10

Have a nice day:)

Mama L [17]2 years ago
3 0

Here,

Length = 2 meters

Breadth = 3 meters

Now,

Perimeter of rectangle = 2 ( l + b )

= 2 ( 2 + 3 )

= 2 * 5

◆ = 10 meters

I hope you understand...

This is a Right answer...

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GREYUIT [131]

Answer:

1.) D

2.) F

3.) C

4.) H

Step-by-step explanation:

i am positive on 4, but not totally sure on 1, 2, and 3

3 0
3 years ago
How to show the tens fact you used. write the difference. <br> 14-6=____<br> 10-___=____
Doss [256]
For this case we have the following expression:
 14 - 6&#10;
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 14 - 6 = 8&#10;
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 tens place: 1
 ones place: 4
 Therefore, number 14 can be rewritten as:
 14 = 10 + 4&#10;
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 14 - 6 = (10 + 4) - 6&#10;
 Then, for associative property we have:
 (10 + 4) - 6 = 10 + (4 - 6)&#10;&#10;10 + (4 - 6) = 10 + (-2)&#10;&#10;10 + (-2) = 10 - 2&#10;&#10;10 - 2 = 8
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 Answer:
 
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3 0
3 years ago
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Can you help please?
hoa [83]

Answer:

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Step-by-step explanation:

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Given nonempty sets A and B, prove that every set in P(B − A) ⊆ P(B) − P(A).
Lelu [443]

Proof:

Let X \in P(B-A). As we chose X in P(B-A) we know that X \subseteq B-A. Since B-A \subseteq B by transitivity we get:

X \subseteq B \quad \implies X \in P(B).

If X is the empty set, we already have that X = \emptyset \in P(B) - P(A). But if X is not empty, that means that it can't be subset of A, because X is already  subset of B-A, and those sets do not share any element. In other words:

X \subseteq A \cup (B-A) = \emptyset

\Rightarrow X = \emptyset

As X can't be subset of A, then X\notin P(A). X was an arbitrary element, and

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Thus, X\in P(B)-P(A), where we conclude that

P(B-A) \subseteq P(B) - P(A)

8 0
3 years ago
Find <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}" alt="a_{1}" align="absmiddle" class="latex-form
yKpoI14uk [10]

Answer:

\displaystyle  a_{1}    = 108

Step-by-step explanation:

we are given

the sum,common difference and nth term of a geometric sequence

we want to figure out the first term

recall geometric sequence

\displaystyle S_{ \text{n}} =  \frac{ a_{1}(1 -  {r}^{n} )}{1 - r}

we are given that

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thus substitute:

\displaystyle 189=  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{1 -  \frac{1}{2} }

to figure out a_1 we need to figure out the equation

simplify denominator:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{2} )}^{3} )}{ \dfrac{1}{2}  }  = 189

simplify square:

\displaystyle  \frac{ a_{1}(1 -  {( \frac{1}{8} )}^{} )}{ \dfrac{1}{2}  }  = 189

simplify substraction:

\displaystyle  \frac{ a_{1} (\frac{7}{8} )}{ \frac{1}{2}  }  = 189

simplify complex fraction:

\displaystyle   a_{1} (\frac{7}{8} ) \div { \frac{1}{2}  }  = 189

calculate reciprocal:

\displaystyle   a_{1} \frac{7}{8}   \times 2  = 189

reduce fraction:

\displaystyle   a_{1} \frac{7}{4}   \  = 189

multiply both sides by 4/7:

\displaystyle   a_{1} \frac{7}{4}  \times  \frac{4}{7}   \  = 189 \times  \frac{4}{7}

reduce fraction:

\displaystyle   a_{1}     = 27\times  4

simplify multiplication:

\displaystyle  a_{1}    = 108

hence,

\displaystyle  a_{1}    = 108

4 0
2 years ago
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