Answer:
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Step-by-step explanation:
For this case we have the following 5 number summary from the data of 144 values:
Minimum: 9 days
Q1: 18 days
Median: 21 days
Q3: 28 days
Maximum: 56 days
The IQR is given by:

If we want to find any possible outliers we can use the following formulas for the limits:


And if we find the lower limt we got:


So then the left boundary for this case would be 3 days
Options are:
Impossible
Certain
Likely
Unlikely
Answer:
Unlikely
Step-by-step explanation:
A ferry is a large ship that carries passengers and loads on water.
A ferry rarely sinks. Infact, the United States experience very low cases of shipwreck yearly. According to wikipedia in 2018, not more than 200 shipwrecks happened all over the world compared to a great number of operations that year.
Therefore, based on statistics, the ferry is unlikely to sink.
30000L is larger than 3kL
Radius of circle= 4
a) circle circumference=2(pi)r
circumference=2(pi)4=25.13
P=2W+2L
p=2(5)+2(10)
P=30
b) area of circle=pi(r^2)=pi(16)=50.27
area of rectangle=L×W= 5×10= 50
c) I think you can figure it put
Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph