HALP ME PLZZ ASAP NO LINKS

A train is traveling at a constant speed of 105 miles per hour. How many feet does it travel in 3 seconds? Remember that 1

ipn [44]

Answer:

in 3 seconds the train should travel 462 feet

Step-by-step explanation:

So, first, we convert the miles into feet.

105 x 5280 = 554400

This means the train travels 554400 feet per hour.

then, we convert the hour, into second.

Since an hour has 60 minutes, and a minute has 60 seconds, we simply multiply:

1(hour) x 60(minutes) x 60(seconds) = 3600

So the train moves 554400 feet every 3600 seconds.

To get how many feet it travels in one second, we divide this by 3600.

3600/3600 and 554400/3600

1 and 154.

For every second the train travels 154 feet.

Then we simply multiply them by 3.

3x1 and 3x154, which equals:

3 and 462.

So the train travels 462 feet every 3 seconds.

I tried to explain this as simply as I can.

I hope its all correct.

6 0

3 years ago

Sarah works at a zoo.

ipn [44]

Answer:

An elephant pregnancy lasts around 22 months, meaning that new born baby elephants are not small! A baby elephant is called a calf and can weigh between 200 and 300 lbs and stand about 3 feet (1 m) tall.

7 0

3 years ago

Read 2 more answers

½ (8x+4) = ¼ (8+16x)

Marina86 [1]

Answer:

Both sides of the equation are equal to each other.

Step-by-step explanation:

½ (8x+4) = ¼ (8+16x)

(1/2*8x) + (1/2*4) = (1/4*8) + (1/4*16x)

4x + 2 = 2 + 4x

(4x - 4x) + 2 = 2 (+ 4x - 4x)

2 = 2

7 0

2 years ago

Lasers can provide highly accurate measurements of small movements. To determine the accuracy of such a laser, it was used to ta

sp2606 [1]

Answer: $p-value \approx 0.01$

Step-by-step explanation:

Hypothesis testing

$\\\left\{\begin{matrix}H_0 : \mu_0 =0\\ H_1: \mu_0 \neq 0\end{matrix}\right.\\$

For this problem, we need to use the t-student distribution to make inference about the data. We calculate the t-statistics as below:

$\bar{X} = 20\:\mu m\\S.E. = 60\:\mu m\\n=82\\t_{stat} = \frac{\bar{X}-\mu_0}{S.E/\sqrt{n}}=\frac{20-0}{60/\sqrt{82}}=3.0185$

Using a t-statistics table, or using the function TDIST in Microsoft Excel with $t_{stat} = 3.0185,\: df (degree\: of\: freedom) = 14 - 1 = 13$ with two-tailed distribution, we obtain $p-value \approx 0.01$ .

4 0

3 years ago

The weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation

Korvikt [17]

Answer:

The z-score of a male bird of this species with a weight of 29.37 grams is 1.7.

Step-by-step explanation:

We are given that the weights of adult male birds of a certain species are normally distributed with a mean of 27.5 grams and a standard deviation of 1.1 grams.

Let X = weights of adult male birds of a certain species

So, X ~ Normal( $\mu=27.5,\sigma^{2} =1.1^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{ X-\mu}{\sigma } }$ ~ N(0,1)

where, $\mu$ = population mean weight = 27.5 grams

$\sigma$ = standard deviation = 1.1 grams

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

SO, the z-score of a male bird of this species with a weight of 29.37 grams is given by;

Z score = $\frac{ X-\mu}{\sigma } }$ = $\frac{ 29.37-27.5}{1.1 } }$

= 1.7

4 0

2 years ago