Question

I need help with this question ( see image). Please show workings.​

Answer 1

Answer:

(a) AC = 12.565 m

(b) bearing of C from A is 90°

(c) BT = 9.373 m

Step-by-step explanation:

(a) extend North line down & perpendicular to AC.

Call that perpendicular intersection "P".

∠BAC = 90° - 53° = 37°

cos 37° = AP/15

0.7986 = AP/15

AP = 11.979 m

∠PNC = 180° - 161° = 19°

∠BCP = 90° - 19° = 71°

18 cm = 0.18 m   (red flag note: 18 cm looks very out of scale for the picture)

cos 71° = CP/0.18

0.3256 = CP/0.18

CP = 0.586 m

AC = 11.979 + 0.586 = 12.565 m

(b) The bearing to C from A is 90°

(c) tan 58° = 15/x

1.6003 = 15/x

x = 9.373 m