Look at the photo I need help pleasse

F(x) = 2x+4 g(x) = x - 7 h(x)=9-x Find f(g(x))

harina [27]

Greetings from Brasil...

We have here a composite function.... Where there is X in function F(X), we will replace by G(X)

F(X) = 2X + 4

G(X) = X - 7

H(X) = 9 - X

F(X) = 2X + 4

F(G(X)) = 2·(GX) + 4

F(G(X)) = 2·(X - 7) + 4

F(G(X)) = 2X - 14 + 4

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see more:

brainly.com/question/17280519

6 0

3 years ago

In this experiment researchers randomly assigned smokers to treatments. Of the 193 smokers taking a placebo, 29 stopped smoking

mezya [45]

Answer:

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances:

Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day.

This means that:

$p_S = \frac{29}{193} = 0.1503$

$s_S = \sqrt{\frac{0.1503*0.8497}{193}} = 0.0257$

Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day.

This means that:

$p_A = \frac{82}{266} = 0.3083$

$s_A = \sqrt{\frac{0.3083*0.6917}{266}} = 0.0283$

Calculate the estimated standard error for the sampling distribution of differences in sample proportions.

$s = \sqrt{s_S^2 + s_A^2} = \sqrt{0.0257^2 + 0.0283^2} = 0.0382$

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

7 0

3 years ago

3(0)+2y=1. Help plzzz

vladimir1956 [14]

Answer:

y=.5 or y=1/2

Step-by-step explanation:

3(0)+2y=1

3 x 0 = 0

0 + 2y = 1

2y = 1

Divide by 2

y=.5 or y=1/2

5 0

4 years ago

Let H and K be subgroups of a group G, and let g be an element of G. The set <img src="https://tex.z-dn.net/?f=%5Cmath%20HgK%20%

34kurt

Answer:

Yes, double cosets partition G.

Step-by-step explanation:

We are going to define a relation over the elements of G.

Let $x,y\in G$ . We say that $x\sim y$ if, and only if, $y\in HxK$ , or, equivalently, if $y=hxk$ , for some $h\in H, k\in K$ .

This defines an equivalence relation over G, that is, this relation is reflexive, symmetric and transitive:

Reflexivity: ( $x\sim x$ for all $x\in G$ .) Note that we can write $x=exe$ , where $e$ is the identity element, so $e\in H,K$ and then $x\in HxK$ . Therefore, $x\sim x$ .
Symmetry: (If $x\sim y$ then $y\sim x$ .) If $x\sim y$ then $y=hxk$ for some $h\in H$ and $k\in K$ . Multiplying by the inverses of h and k we get that $x=h^{-1}yk^{-1}$ and is known that $h^{-1}\in H$ and $k^{-1}\in K$ . This means that $x\in HyK$ or, equivalently, $y\sim x$ .

Transitivity: (If $x\sim y$ and $y\sim z$ , then $x\sim z$ .) If $x\sim y$ and $y\sim z$ , then there exists $h_1,h_2\in H$ and $k_1,k_2\in K$ such that $y=h_1xk_1$ and $z=h_2yk_2$ . Then, $\\ z=h_2yk_2=h_2(h_1xk_1)k_2=(h_2h_1)x(k_1k_2)=h_3xk_3$ where $h_3=h_2h_1\in H$ and $k_3=k_1k_2\in K$ . Consequently, $z\sim x$ .

Now that we prove that the relation " $\sim$ " is an equivalence over G, we use the fact that the different equivalence classes partition G. Since the equivalence classes are defined by $[x]=\{y\in G\colon x\sim y\} =\{y\in G \colon y=hgk\ \text{for some } h\in H, k\in K \}=HxK$ , then we're done.

5 0

3 years ago

68 of _______ = 85 how do you get 85 do 68 of blank % = 85

faust18 [17]

X=80 Explanation:

68=x⋅85100

x=68⋅10085

x=80

5 0

3 years ago