Is 5.333333 rational or irrational
2 answers:
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Answer:
Option B) 16
Step-by-step explanation:
We are given the following in the question:
where x is the student's original test score and y is the student's adjusted test score.
We have to find the standard deviation of the adjusted test scores of the students in the class, if the standard deviation of the original test scores of the students in the class was 20.
We know that:
- Adding a constant to each value in a data set does not change the value of the standard deviation.
- Multiplying each value in a data set by a constant also multiplies the standard deviation by that constant.
Thus, if we add 20 to each data set then, the standard deviation does not change.
But multiplying each score by 0.8, changes the standard deviation 0.8 times.
Thus, we can write:
Thus, standard deviation of adjusted score is 16.
Answer:
T1(n) = 25n +119.50 where n belongs to .
T2(n) = 20n + 59 where n belongs to .
Step-by-step explanation:
We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.
Let the number of person going for this restaurant be "n"
For normal day, we are given
catering service = $25 per person
service charge = $119.50
Let the total cost of the restaurant be T
Cost for this case will be T1
T1(n) = 25n +119.50 where n belongs to
similarly for the case when 50 or more than that goes to this restaurant for party.
cost after discount
Catering service = $20.00 per person
service charge = $59.00
now the cost of this case will be T2
T2(n) = 20n + 59 where n belongs to .
Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.