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balu736 [363]
3 years ago
8

A restaurant offers a catering service which costs $25.00 per person with a $119.50 service charge. For parties of 50 or more pe

ople, a group discount applies, and the cost is $20.00 per person along with the service charge dropping to $59.00. (a) Write a piecewise-defined linear function which calculates the total cost T of the catering service which serves n people.
Mathematics
1 answer:
Molodets [167]3 years ago
7 0

Answer:

T1(n) = 25n +119.50  where n belongs to 1 \leq n.

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Step-by-step explanation:

We are given two situations first is for normal days and the other is for days when 50 or more people are going to this restaurant for the party.

Let the number of person going for this restaurant be "n"

For normal day, we are given

catering service = $25 per person

service charge = $119.50  

Let the total cost of the restaurant be T

Cost for this case will be T1  

T1(n) = 25n +119.50  where n belongs to 1 \leq n

similarly for the case when 50 or more than that goes to this restaurant for party.

cost after discount

Catering service = $20.00 per person

service charge = $59.00

now the cost of this case will be T2

T2(n) = 20n + 59 where n belongs to 50\leq  n.

Therefore the two piecewise linear functions represents the total cost of the restaurant for serving n people.  

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Write the numerical expression in words two different ways. 7/ (10-3)
MissTica

Answer:

seven divided by the difference of ten and three

seven over the difference of ten and three

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3 years ago
3. The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population p
damaskus [11]

Answer:

A)sample proportion = 0.17,  the sampling distribution of p can be calculated/approximated with normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) 0.869

C)0.9668

Step-by-step explanation:

A) p ( proportion of population that spends more than $100 per week) = 0.17

sample size (n)= 800

the sample proportion of p = 0.17

standard error of p = \sqrt{\frac{p(1-p)}{n} } = 0.013281

the sampling distribution of p can be calculated/approximated with

normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) probability that the sample proportion will be +-0.02 of the population proportion

= p (0.17 - 0.02 ≤ P ≤ 0.17 + 0.02 ) = p( 0.15 ≤ P ≤ 0.19)

z value corresponding to P

Z = \frac{P - p}{standard deviation}

at P = 0.15

Z =  (0.15 - 0.17) / 0.013281 = = -1.51

at P = 0.19

z = ( 0.19 - 0.17) / 0.013281 = 1.51

therefore the required probability will be

p( -1.5 ≤ z ≤ 1.5 ) = p(z ≤ 1.51 ) - p(z ≤ -1.51 )

                           = 0.9345 - 0.0655 = 0.869

C) for a sample (n ) = 1600

standard deviation/ error = 0.009391 (applying the equation for calculating standard error as seen in part A above)

therefore the required probability after applying

z = \frac{P-p}{standard deviation} at p = 0.15 and p = 0.19

p ( -2.13 ≤ z ≤ 2.13 ) = p( z ≤ 2.13 ) - p( z ≤ -2.13 )

                               = 0.9834 - 0.0166 = 0.9668

7 0
3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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For example:

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LCM(35,18)=630

Since Tom, Sam, and Matt are counting drum beats at their own frequency, we must find the least common multiple of all their beats frequency.

Find the LCM of 4,10,12. Follow this procedure:

List prime factorization of all the numbers:

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Multiply all the factors the greatest times they occur:

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Thus, when 60 beats are heard, Tom hits 15 snare drums, Sam hits 6 kettle drums, and Matt hits 5 bass drums.

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nasty-shy [4]

Answer:

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Hope this helps you

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