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bagirrra123 [75]
3 years ago
15

If PQRS is a rhombus, find m

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

m<PQR = 82°

Step-by-step explanation:

In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.

Therefore:

(4x - 27)° = (2x + 7)°

Solve for x

4x - 27 = 2x + 7

Collect like terms

4x - 2x = 27 + 7

2x = 34

Divide both sides by 2

2x/2 = 34/2

x = 17

✔️m<PQR = (4x - 27) + (2x + 7)

Plug in the value of x

m<PQR = (4*17 - 27) + (2*17 + 7)

m<PQR = 41 + 41

m<PQR = 82°

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