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bagirrra123 [75]
3 years ago
15

If PQRS is a rhombus, find m

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

m<PQR = 82°

Step-by-step explanation:

In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.

Therefore:

(4x - 27)° = (2x + 7)°

Solve for x

4x - 27 = 2x + 7

Collect like terms

4x - 2x = 27 + 7

2x = 34

Divide both sides by 2

2x/2 = 34/2

x = 17

✔️m<PQR = (4x - 27) + (2x + 7)

Plug in the value of x

m<PQR = (4*17 - 27) + (2*17 + 7)

m<PQR = 41 + 41

m<PQR = 82°

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3 years ago
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igomit [66]

Answer:

Mean = 1.57

Variance=0.31

Step-by-step explanation:

To calculate the mean and the variance of the number of successful surgeries (X), we first have to enumerate the possible outcomes:

1) Both surgeries are successful (X=2).

P(e_1)=0.90*0.67=0.603

2) Left knee unsuccessful and right knee successful (X=1).

P(e_2)=(1-0.9)*0.67=0.1*0.67=0.067

3) Right knee unsuccessful and left knee successful (X=1).

P(e_3)=0.90*(1-0.67)=0.9*0.33=0.297

4) Both surgeries are unsuccessful (X=0).

P(e_4)=(1-0.90)*(1-0.67)=0.1*0.33=0.033

Then, the mean can be calculated as the expected value:

M=\sum p_iX_i=0.603*2+0.067*1+0.297*1+0.033*0\\\\M=1.206+0.067+0.297+0\\\\M=1.57

The variance can be calculated as:

V=\sum p_i(X_i-\bar{X})^2\\\\V=0.603(2-1.57)^2+(0.067+0.297)*(1-1.57)^2+0.033*(0-1.57)^2\\\\V=0.603*0.1849+0.364*0.3249+0.033*2.4649\\\\V=0.1115+0.1183+0.0813\\\\V=0.3111

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4. The image coordinates are 5 times the original coordinates, so ...

... the scale factor of the dilation is 5.

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3 years ago
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