Answer:
P(A U B)= 0.08
Step-by-step explanation:
1.Let:
P(A) as the probability that a psiton has an under-fill defect
P(B) as the probability that a pistón has a porosity defect
P(A ∩ B) the probability of having both defectos
Then:
P(A)=0.05
P(B)=0.04
P(A ∩ B)=0.01
2. The probability that a randomly chosen piston has a defect could be calcularse as the union of the probability of choosing a piston with am under-fill defect and one with porosity defect.
That Is P(A U B)
Aplying the probability properties we have:
P(A U B)= P(A) + P(B) -P(A ∩ B)
Replacing the probabilities:
P(A U B)= 0.05+0.04-0.01
P(A U B)= 0.08
Answer: 65%, 195 children
Step-by-step explanation: To get this, we just do 100-35 to get 65 percent. We can calculate this further, and do 300*0.65, and we get 195. Thus, there were 195 children.
Answer: C=[ (10) x (19.60)÷ (8)]
Step-by-step explanation:
Given , The cost of 8 books = $ 19.60
Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)
i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)
Now , cost of 10 books = (10) x (Cost of one book)
From (i) , we get
Cost of 10 books =$[ (10) x (19.60)÷ (8)]
Let C be the cost of 10 books ( in dollars) .
So , the equation would help determine the cost of 10 :
C=[ (10) x (19.60)÷ (8)]
So I'm hoping you mean 6, or else the probability is 0. So the possible ways of getting a sum of 6 is 1&5, 2&4, 3&3, 4&2, 5&1. There are 36 different ways of rolling the dice, so divide the 5 possible ways by 36. Then, we need to add the possibility of getting at least one 6 in the roll. It doesn't matter what the other die is, so for each die, the probability is 1/6, and for both, the probability is 2/6. Add this to the probability of getting a sum of 6, and you get your answer.
Answer:
4 cm, if you subtract 9 from 13 you get four.
