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Alborosie
3 years ago
13

Brainlyist for the right answer

Mathematics
2 answers:
Kay [80]3 years ago
5 0

Answer:

c, a

Step-by-step explanation:

c, a is TRUE.

i hope that is correct

muminat3 years ago
4 0

Answer:

A and C are the correct answers

Step-by-step explanation:

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dangina [55]
A.

5-1=\boxed{4}\\\\10-5=\boxed{5}

Not an arithmetic sequence.

B.

-27-(-20)=-27+20=\boxed{-7}\\\\-34-(-27)=-34+27=\boxed{-7}

An arithmetic sequence.

Answer B.
5 0
3 years ago
Please I need help I have no idea how to do this and it’s due soon!
Anon25 [30]
I do this but I don’t remember how
8 0
4 years ago
During bully’s first week working in China shop he breaks a vase that cost $45.89 two glasses that cost $16.25 each and a platte
max2010maxim [7]

He will have to work 40.73 hours to pay off the things he broke

First we add the cost of all the things he broke, then we divide that by 5,25 and we get our answer

5 0
4 years ago
Read 2 more answers
The following probability distributions of job satisfaction scores for a sample of information systems (IS) senior executives an
Mashcka [7]

Answer:

Step-by-step explanation:

To calculate ;

1) the expected value of the job satisfaction score for senior executives ;

expected value = Summation (Px)

= 1 x 0.05 + 2 x 0.09 + 3 x 0.03 + 4 x 0.42 + 5 x 0.41

= 4.05

2) the expected value of the job satisfaction score for middle managers;

= 1 x 0.04 + 2 x 0.10 + 3 x 0.12 + 4 x 0.46 + 5 x 0.28

= 3.84

c) the variance of job satisfaction scores for executives and middle managers (to 2 decimals).

Executives ; Variance = Summation(PX^2 - Summation(PX)^2

i) For Executive Managers = 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2 = 1.246 = 1.25

ii) for middle managers ; 1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 = 1.134 = 1.13

d) the standard deviation of job satisfaction scores for both probability distributions (to 2 decimals). Executives, Middle managers;

For Executives = square root [ 1 x 0.05 + 2^2 x 0.09 + 3^2 x 0.03 + 4^2 x 0.42 + 5^2 x 0.41 - 4.05^2] = 1.12

For Middle Managers ; Square root [1 x 0.04 + 2^2 x 0.10 + 3^2 x 0.12 + 4^2 x 0.46 + 5^2 x 0.28 - 3.84^2 ] = 1.06

e) from the values gotten for the variance of both executive and middle managers, the variance of the former is more than that of the latter as such higher satisfaction with the executive managers.

5 0
3 years ago
in the computer lab there are 14 Apple computers and 16 PC computers. Approximately what percent of the computers are PCs?
ad-work [718]


So first we take the total number of computers. Which will be 14 + 16 = 30 computers.

Since we have 16 pc computers, we will divide 16 by 30 and multiply it by 100 to get the percentage:

So: (16/30) x 100

There are 53.33% PC computers in the computer lab.

6 0
4 years ago
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