Question

1. A right triangle LMN is given where: side MN = 8 side NL (the hypotenuse) =

Answer 1

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

• Length of MN ( Base ) = 8
• Length of NL ( Hypotenuse ) = 10

$\underline{ \underline{ \text{To \: find}}} :$

• Length of LM ( Perpendicular )

$\underline{ \underline{ \text{Using \: pythagoras \: theorem}}} :$

$\boxed{ \sf{ {Hypotenuse}^{2} = {Perpendicular}^{2} + {Base}^{2} }}$

⤑ $\sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^{2} - {(Base)}^{2} } }$

⤑ $\sf{ \sqrt{ {(10)}^{2} - {(8)}^{2} } }$

⤑ $\sf{ \sqrt{100 - 64}}$

⤑ $\sf{ \sqrt{36}}$

⤑ $\boxed{ \sf{6\: units}}$

$\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}$

Hope I helped ! ツ

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