If the inscribed square has sides of 8in, the diameter of the circle is equal to the diagonal of the square.
d^2=x^2+x^2
d^2=2x^2
d=√(2x^2)
Since d=2r, r=d/2 so
r=(1/2)√(2x^2)
r=√((2x^2)/4)
r=√(x^2/2), since x=8
r=√(64/2)
r=√32
r=√(16*2)
r=4√2 in (exact)
r≈5.66 in (to nearest hundredth of an inch)
Answer:
I think the first one is power ( if not then coefficient) and the second is definitely expression
Step-by-step explanation:
The answer is

and

. A picture is attached to explain what alternate exterior angles are.
Answer:
5) a)(-4,-6) b) (4,2) c) (2,6) 6) (3,2)
Step-by-step explanation:
5) the solution is the points where the lines meet.
6) graphed the lines; the picture of the graph is attached below