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JulijaS [17]
2 years ago
13

Name an angle supplementary to BDC PLEASE HELP ASAP!!

Mathematics
1 answer:
NNADVOKAT [17]2 years ago
4 0
The answer is angle FDE , hope it helps
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Below are the data collected from two random samples of 500 American students on the number of hours they spend in school per da
balu736 [363]

Answer: <em>Tara thinks correctly.</em>

Step-by-step explanation:

<em>Let's calculate the average value in sample A:</em>

<em>(4 × 70 + 5 × 100 + 6 × 125 + 7 × 135 + 8 × 70) ÷ 500 = 6,07 ≈ </em><em>6 hours</em>

<em>Let's calculate the average value in sample B:</em>

<em>(4 × 80 + 5 × 90 + 6 × 120 + 7 × 125 + 8 × 85) ÷ 500 = 6,09 ≈ </em><em>6 hours</em>

<em>So, Tara is correct in saying that the mean is 6.</em>

3 0
3 years ago
2 = f/8 <br><br><br> f= ? <br> Pleaze helpsz me i will give you robux I promise !!
Ilia_Sergeevich [38]

Answer:

f = 16

Step-by-step explanation:

2 = f/8

Cross Multiplying, we get

f = 16

hope it helps!

8 0
3 years ago
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Kaylee is selling candles to raise money for her lacrosse team. The large candles sell for $25 each and the
AVprozaik [17]

Answer:25(20)+10(10)=600

X Y

Step-by-step explanation: sell 20 (X) Large candles and sell 10 (Y) small candles

3 0
3 years ago
Solve. 90<img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formula"> = 27.
Irina-Kira [14]

Answer: x≈0.732

Step-by-step explanation:

You need to find the value of the variable "x".

To solve for "x" you need to apply the following property of logarithms:

log(m)^n=nlog(m)

Apply logarithm on both sides of the equation:

90^x=27\\\\log(90)^x=log(27)

Now, applying the property mentioned before, you can rewrite the equation in this form:

xlog(90)=log(27)

Finally, you can apply the Division property of equality, which states that:  

 If\ a=b,\ then\ \frac{a}{c}=\frac{b}{c}

Therefore, you need to divide both sides of the equation by log(90). Finally, you get:

\frac{xlog(90)}{log(90)}=\frac{log(27)}{log(90)}\\\\x=\frac{log(27)}{log(90)}

x≈0.732

7 0
3 years ago
One hundred times the quantity six plus five
Andru [333]
100 times (6+5)
100 times 11
100 groups of 11=1100
Hope I helped:)

3 0
3 years ago
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