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3 years ago

A beverage company surveyed 450 adults to determine the demand for summer drinks.

Mathematics

2 answers:

arlik [135]3 years ago

5 0

Answer:

D: 276 preferred water

Step-by-step explanation:

nikklg [1K]3 years ago

4 0

Answer:

Step-by-step explanation:

total number of people minus people who prefer soda, iced tea, or lemonade= people who prefer water

450-101-67-108=174

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Why was Florence such an ideal city for artistic expression? a. Most artists were born in Florence. b. Florence promoted economi

iren2701 [21]

Answer:

B. Florence promoted economic and social freedom

Step-by-step explanation:

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3 years ago

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Vitek1552 [10]

Answer:

2nd one

Step-by-step explanation:

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4 years ago

The Census Bureau says that the 10 most common names in the United States are (in order) Smith, Johnson, Williams, Jones, Brown,

scZoUnD [109]

Using binomial distribution where success is the appearing of any of the top 10 most common names, thus probability of success (p) is 9.6% = 0.096 and the probability of failure = 1 - 0.096 = 0.904. Number of trials is 11.
Binomial distribution probability is given by P(x) = nCx (p)^x (q)^(n - x)
Probability that none of the top 10 most common names appears is P(0) = 11C0 (0.096)^0 (0.904)^(11 - 0) = (0.904)^11 = 0.3295
Thus, the probability that at least one of the 10 most common names appear is 1 - 0.3295 = 0.6705

Therefore, I will be supprised that none of the names of the authors were among the 10 most common names given that the probability that at least one of the names appear is 67%.

6 0

3 years ago

Clayton plays basketball on a team. He has played three games so far . In the first game, he scored 10 points. In the second gam

Fofino [41]

Answer:

Clayton's average points per game is 10

Step-by-step explanation:

To find an average add all the numbers and divide the sum by the amount of numbers added.

In this case, 10 + 14 + 6 = 30. $\frac{30}{3}$ = 10

Hope this helps!

-MoCKEry

3 0

3 years ago

Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .

8 0

3 years ago