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Nina [5.8K]
3 years ago
15

Explain the process and the properties you have to use to solve the logarithmic equation: log(3)x + log(3)4 - 2 log(3)3 = 2

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

81/4

Step-by-step explanation:

log_{3}(  \frac{4x}{{3}^{2} }   )  = 2

{3}^{2}  =  \frac{4x}{ {3 }^{2} }

9=4x/9

81=4×

x=81/4

adding logs means elements are multiplied, subtracting means divide. number in front of log is raised to power

base of log is raised to power of element after =

element in log is then equal to log base raised to power

solve resulting equation

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Solve A=p+prt for r.
Furkat [3]

A = p + prt

The above equation can be solved for “r” in such a way.

Subtract “p” from both sides;

A – p = p + prt – p

A – p = prt

Divide both sides by “p” and “t”;

A/pt – p/pt = prt/pt

A/pt – 1/t = r

Or

<span>r =  A/pt – 1/t</span>

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3 years ago
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Answer:

A.

Step-by-step explanation:

x^0=1 so you can cancel it out. when a number has a negavite exponent, you have to invert it. That means y^-6 goes at the denominator and becomes y^6 and z^-6 goes up to the numerator and becomes z^6.

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3 years ago
Which compares the modes of the data? The mode for the students is 2 and the mode for the teachers is 4. The mode for the studen
motikmotik

Answer:

B

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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SOVA2 [1]
Notice the picture below

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now, "p" is the distance from the vertex to the focus point or the directrix, so that means, the vertex is between those two fellows, over the axis of symmetry, x = -2, since "p" is 1 unit, that puts the vertex at -2,5

since the parabola is opening downwards, that means the "p" value is negative, so is -1

\bf \textit{parabola vertex form with focus point distance}\\\\&#10;\begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}}) }\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}\\\\&#10;-----------------------------\\\\

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3 years ago
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