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docker41 [41]
3 years ago
7

Indicate the answer choice that best completes the statemer

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

25

Step-by-step explanation:

-25 to 0 is 25 and 25 to 0 is 25

Opposite of -25 is 25

So lettter d

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n a booster club, 1⁄8 of the 128 members are men. How many male members are in the club? A. 64 B. 112 C. 16 D. 1
Ber [7]
1/8 x 128 = 16

There are 16 male members
5 0
3 years ago
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The cross country team practice by jogging on town steerts the average jogging rate is 6 mile per hour one member jogged for 3.5
seropon [69]

Answer:

6mile + hour + 3.5 hours + miles

Step-by-step explanation:

add the expressions

8 0
2 years ago
Help me solve,Brainlist for first to answer
Vanyuwa [196]

Answer:

(i) the other two sides are 6 and  6\sqrt{2}

(ii) the other two sides are   \frac{4}{3} and                                         \frac{8}{3}

Step-by-step explanation:

(i)  Sine: sin(θ) = Opposite ÷ Hypotenuse

    Cosine: cos(θ) = Adjacent  ÷ Hypotenuse

    Tangent: tan(θ) = Opposite ÷ Adjacent

Here adjacent side = 6

opposite side = d

angle = 45°

other angles are 90° and 45°

tan (45) = Opposite ÷ Adjacent

 1 = d ÷ 6

∴ d = 6 × 1 = 6

so opposite side = 6

Hypotenuse ² = opposite side ² + adjacent side²

                      =  6² + 6²

                      = 36 + 36

                       = 72

hypotenuse = \sqrt{72}

                     = 6\sqrt{2}

the other two sides are 6 and  6\sqrt{2}

(ii) here adjacent side = 4√3

angle = 30°

other angles are 90° and 60°

opposite side = d

tan ( 30) = opposite ÷ adjacent

 \frac{1}{\sqrt{3}} = d ÷ 4√3

\frac{1}{\sqrt{3}} = d × (\frac{\sqrt{3}}{4})

                       3 d = 4

therefore d = \frac{4}{3}

therefore opposite side = \frac{4}{3}

Hypotenuse ² = opposite side ² + adjacent side²

                        =( \frac{4}{3})² +( \frac{4}{\sqrt{3}})²

                        = \frac{64}{9}

therefore hypotenuse = \sqrt{\frac{64}{9}}

                                     =\frac{8}{3}

the other two sides are   \frac{4}{3} and                                    \frac{8}{3}

7 0
3 years ago
Find the non-extraneous solutions of the square root of the quantity x plus 6 minus 5 equals quantity x plus 1.
denis23 [38]
(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous

3 0
3 years ago
What is the length of PQ , rounded to the nearest tenth.
Assoli18 [71]

Answer:

10.8 units

Step-by-step explanation:

7 0
2 years ago
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