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2 years ago

Can somebody help me asap?

Mathematics

1 answer:

Oduvanchick [21]2 years ago

8 0

Answer:

44%

Step-by-step explanation:

First, take that pretty figure and align it into complete rows.

It will make 2 full rows plus one block.

1 row is 20% since 100 / 5 blocks is 20.

That's 11 blocks.

11 / 25 = .44 or 44%

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Subtract.

ycow [4]

-27 - (-3) = -27 + 3 = - 24

560 - 2(25 + 11) = 560 - 2(36) = 560 - 72 = 488

8y - x^2....x = -5, y = 4
8(4) - (-5)^2 =
32 + 5^2 =
32 + 25 =
57

3 0

3 years ago

PLEASE HELP ASAP PLEASE

emmainna [20.7K]

Answer:

The equation that represents the line passing through the point (2, -4) with a slope of one half is

$f(x) = \frac{1}{2}x - 5$

Step-by-step explanation:

The equation of a line can be described by a first order equation in the following format:

$f(x) = ax + b$

In which a is the slope of the line.

Solution:

The line slope is $\frac{1}{2}$ , so $a = \frac{1}{2}$ .

The equation of the line now is:

$f(x) = \frac{1}{2}x + b$

The problem states that the line passes through the point(2,-4). This means that when x = 2, f(x) = -4

So:

$f(x) = \frac{1}{2}x + b$

$-4 = \frac{1}{2}*(2) + b$

$-4 = 1 + b$

$b = -5$

So, the equation that represents the line passing through the point (2, -4) with a slope of one half is

$f(x) = \frac{1}{2}x - 5$

3 0

2 years ago

a circle has a center (3,5) and a diameter AB. The coordinates of A are (-4,6). what are the coordinates of B?

Kruka [31]

Find the length of the radius.

$r= \sqrt{(3-(-4))^2+(5-6)^2}
\\r = \sqrt{7^2+(-1)^2}
\\r= \sqrt{50} 
\\ r=5 \sqrt{2}$

Find the length of the diameter.

d = 2r = 2 × 5√2 = 10√2

Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)

$y-y_1= \frac{y_2-y_1}{x_2-x_1}(x-x_1)
\\y-6= \frac{5-6}{3-(-4)} (x-(-4))
\\y-6=- \frac{1}{7} (x+4)
\\7y-42=-x-4
\\x+7y-38=0$

The distance from B(x, y) to C(3, 5) is 5√2.
$\sqrt{(x-3)^2+(y-5)^2}=5 \sqrt{2} 
 \\(x-3)^2+(y-5)^2=(5 \sqrt{2})^2 
\\(x-3)^2+(y-5)^2=50$

Solve system of equations.
$x+7y-38=0
\\(x-3)^2+(y-5)^2=50
\\
\\x=38-7y
\\(38-7y-3)^2+(y-5)^2=50
\\(35-7y)^2+(y-5)^2=50
\\1225-490y+49y^2+y^2-10y+25-50=0
\\50y^2-500y+1200=0
\\y^2-10y+24=0
\\y^2-6y-4y+24=0
\\y(y-6)-4(y-6)=0 \\(y-6)(y-4)=0 \\y_1=6,y_2=4
$

$x_1=38-7y_1=38-7 \times 6 = 38-42=-4
\\x_2=38-7y_2=38-7 \times 4 = 38-28=10
$

Point B could have coordinates
$\\
\\(x_1,y_1)=(-4,6),(x_2,y_2)=(10,4)
$

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).

8 0

3 years ago

Ben and Corinne are filling goodie bags for a party. Each goodie bag needs an eraser, a bubble wand, and a few candy bar bites.

Fudgin [204]

Answer:

Ben

Step-by-step explanation:

Corinne is slower

3 0

3 years ago

An arithmetic sequence a starts 2, 5, . .

Whitepunk [10]

Answer:

Tn = 3n-1

T6 = 17

Step-by-step explanation:

Given the arithmetic sequence;

2, 5...

first term a = 2

Common difference d = 5-2 = 3

nth term of an AP is expressed as Tn = a + (n-1)d

Tn = 2 + (n-1)(3)

Tn = 2 + 3n-3

Tn = 3n-1

Get the 6th term

T6 = 3(6)-1

T6 = 18-1

T6 = 17

Hence the 6th term of the sequence is 17

6 0

2 years ago