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2 years ago

If a right angle triangle has one side with 3cm and the other with 4cm how do i get the last side

Mathematics

1 answer:

Gnesinka [82]2 years ago

7 0

Answer:

5cm

Step-by-step explanation:

It is the pythagorean Theorem and there is this special rule my teacher always told me to follow that means it is always 3, 4, and 5. Trust me, I had this problem before. It is 5cm just use the pythagorean theorem.

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A volleyball curt is 61 feet lenght and 21 feet wide. How much rope will you use to mark the outline on the court?

lozanna [386]

So finding the rope is kind of like finding the perimeter. Add 61+61+21+21 and you will get 164 feet.

8 0

2 years ago

A hypothesis is only tentative: to make sure it's valid, you have to ___________.

GREYUIT [131]

A hypothesis is only tentative: to make sure it's valid, you have to test it.

4 0

3 years ago

Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth

Anika [276]

Answer:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have that the quadratic formula is:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

$2x^{2}-5x-1=0$

$a=2\\b=-5\\c=-1$

Then you have:

$x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}$

3. Therefore, you obtain the following result:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

4 0

2 years ago

Read 2 more answers

Billy was counting the number of wheels and bike seats at the playground. He saw tricycles and bicycles. He counted 79 wheels an

mart [117]

I think the answer is 25.5. Although, I don't know how you would have half a bike unless there was a 3 wheel bike which would make the answer 24.

7 0

3 years ago

I need the domain range and function. With an explanation

erastovalidia [21]

<h3>Answers:</h3>

Problem 1

Domain = $-3 < x \le 3$ , interval notation (-3, 3]
Range = $-3 \le y < 3$ , interval notation [-3, 3)
Is it a function? Yes

Problem 2

Domain = $x \ge -2$ , interval notation $[-2, \infty)$
Range = All real numbers, interval notation $(-\infty, \infty)$
Is it a function? No

Problem 3

Domain = $-4 \le x < 3$ , interval notation [-4, 3)
Range = $-4 < y \le 3$ , interval notation (-4, 3]
Is it a function? Yes

Problem 4

Domain = All real numbers, interval notation $(-\infty, \infty)$
Range = $y \le 4$ , interval notation $(-\infty, 4]$
Is it a function? Yes

==================================================

Explanations:

The left most point is when x = -3, and we are not including this value due to the open hole. The other endpoint is included because it is a filled in circle. The domain is therefore $-3 < x \le 3$ which in interval notation is (-3, 3]. We have the curved parenthesis meaning "exclude endpoint" and the square bracket says "include endpoint". The range is a similar story but we're looking at the smallest and largest y values. Though be careful about which endpoint is open/closed. We have a function because it passes the vertical line test.
The smallest x value is x = -2. There is no largest x value because the arrows say to go on forever to the right. We can say the domain is $x \ge -2$ which in interval notation is $[-2, \infty)$ . The range is $(-\infty, \infty)$ to indicate "all real numbers". This graph fails the vertical line test, so it is not a function. The vertical line test is where we check to see if we can pass a vertical line through more than one point on the curve. In this case, such a thing is possible which is why it fails the test.
This is the same idea as problem 1, though note the endpoints are flipped in terms of which has an open circle and which doesn't. It is not possible to draw a single vertical line to have it pass through more than one point on the curve, so it passes the vertical line test and we have a function.
This is a function because it passes the vertical line test. The domain is the set of all real numbers due to the arrows in both directions. Any x value is a possible input. The range is $y \le 4$ which is the same as saying $(-\infty, 4]$ in interval notation. This is because y = 4 is the largest y value possible. There is no smallest y value due to the arrows.

7 0

3 years ago